## Re: [nanotech] XPS

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• Zeynep, I extensively used XPS during my masters on nanoceria. Ce can present in both Ce3+ and Ce4+. I have total of 10 peaks for Cerium (out of which 6 are
Message 1 of 11 , May 11 7:04 AM
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Zeynep,
I extensively used XPS during my masters on nanoceria. Ce can present in
both Ce3+ and Ce4+. I have total of 10 peaks for Cerium (out of which 6 are
from Ce3+ and 4 are from Ce4+). To find the Ce3+ to Ce4+ ratio, I calculated
it as a ratio of Area under all the 6 corresponding peaks to Area under 4
corresponding peaks.
(All the calculations are based on B.E)

so I suggest, find what are the oxidation states of the element and then
which peaks corresponds to which oxidation states. Area under the curve is
the good representation of how much of that state present in it.

XPS is a powerful tool to analyze oxidation states.

Thanks
Ranjith

>
>
> dear different energies corrospond to different elements, if your plot have
> K.E versus Intensity. you have to convert it first into B.E by simple
> Photoeletric formula, I dont know what was youe exasct question.
> Regards
>
>
> ________________________________
>
> From: zeynep meric <zeyno_ms@... <zeyno_ms%40yahoo.com>>
> To: nanotech@yahoogroups.com <nanotech%40yahoogroups.com>
> Sent: Monday, May 11, 2009 9:10:10
> Subject: Re: [nanotech] XPS
>
> thanks a lot.
> but all these Xps handbooks shows diffrent energies for elements.What
> causes the difference of these energies?
>
> ____________ _________ _________ __
> From: Pankaj Gupta <pankajgupta78@ yahoo.com>
> To: nanotech@yahoogroup s.com
> Sent: Monday, May 11, 2009 4:04:03 AM
> Subject: Re: [nanotech] XPS
>
> Zeynep,
>
> XPS handbooks are good source of most of the peaks. I am not sure, what
> material you are working with, but there are some novel peaks, you might
> have to dig through literature.
>
> Thanks
> Pankaj
>
> --- On Sat, 5/9/09, zeynep meric <zeyno_ms@yahoo. com> wrote:
>
> From: zeynep meric <zeyno_ms@yahoo. com>
> Subject: [nanotech] XPS
> To: nanotech@yahoogroup s.com
> Date: Saturday, May 9, 2009, 11:20 AM
>
> Hello for everyone
> Is there anybody that know XPS meansX-ray photoelectron spectroscopy.
> I have data and a graph and � found out some peak's elemental meaning but
> stil I am not clear about that.Is there anybody that can explain all
> peaks?or sent me any book paper or smt else about that.
>
> ZEYNEP MER��
> (MASTER STUDENT)
>
> [Non-text portions of this message have been removed]
>
> [Non-text portions of this message have been removed]
>
> [Non-text portions of this message have been removed]
>
> New Email names for you!
> Get the Email name you've always wanted on the new @ymail and
> @rocketmail.
> Hurry before someone else does!
> http://mail.promotions.yahoo.com/newdomains/aa/
>
> [Non-text portions of this message have been removed]
>
>
>

[Non-text portions of this message have been removed]
• thanks a lot but this is so complicated than ı expect.ı will try   ... From: ranjith kumar To: nanotech@yahoogroups.com Sent:
Message 2 of 11 , May 11 1:48 PM
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thanks a lot but this is so complicated than ı expect.ı will try

----- Original Message ----
From: ranjith kumar <ranjith2882@...>
To: nanotech@yahoogroups.com
Sent: Monday, May 11, 2009 5:04:41 PM
Subject: Re: [nanotech] XPS

Zeynep,
I extensively used XPS during my masters on nanoceria. Ce can present in
both Ce3+ and Ce4+. I have total of 10 peaks for Cerium (out of which 6 are
from Ce3+ and 4 are from Ce4+). To find the Ce3+ to Ce4+ ratio, I calculated
it as a ratio of Area under all the 6 corresponding peaks to Area under 4
corresponding peaks.
(All the calculations are based on B.E)

so I suggest, find what are the oxidation states of the element and then
which peaks corresponds to which oxidation states. Area under the curve is
the good representation of how much of that state present in it.

XPS is a powerful tool to analyze oxidation states.

Thanks
Ranjith

>
>
> dear different energies corrospond to different elements, if your plot have
> K.E versus Intensity. you have to convert it first into B.E by simple
> Photoeletric formula, I dont know what was youe exasct question.
> Regards
>
>
> ________________________________
>
> From: zeynep meric <zeyno_ms@... <zeyno_ms%40yahoo.com>>
> To: nanotech@yahoogroups.com <nanotech%40yahoogroups.com>
> Sent: Monday, May 11, 2009 9:10:10
> Subject: Re: [nanotech] XPS
>
> thanks a lot.
> but all these Xps handbooks shows diffrent energies for elements.What
> causes the difference of these energies?
>
> ____________ _________ _________ __
> From: Pankaj Gupta <pankajgupta78@ yahoo.com>
> To: nanotech@yahoogroup s.com
> Sent: Monday, May 11, 2009 4:04:03 AM
> Subject: Re: [nanotech] XPS
>
> Zeynep,
>
> XPS handbooks are good source of most of the peaks. I am not sure, what
> material you are working with, but there are some novel peaks, you might
> have to dig through literature.
>
> Thanks
> Pankaj
>
> --- On Sat, 5/9/09, zeynep meric <zeyno_ms@yahoo. com> wrote:
>
> From: zeynep meric <zeyno_ms@yahoo. com>
> Subject: [nanotech] XPS
> To: nanotech@yahoogroup s.com
> Date: Saturday, May 9, 2009, 11:20 AM
>
> Hello for everyone
> Is there anybody that know XPS meansX-ray photoelectron spectroscopy.
> I have data and a graph and ý found out some peak's elemental meaning but
> stil I am not clear about that.Is there anybody that can explain all
> peaks?or sent me any book paper or smt else about that.
>
> ZEYNEP MERÝÇ
> (MASTER STUDENT)
>
> [Non-text portions of this message have been removed]
>
> [Non-text portions of this message have been removed]
>
> [Non-text portions of this message have been removed]
>
> New Email names for you!
> Get the Email name you've always wanted on the new @ymail and
> @rocketmail.
> Hurry before someone else does!
> http://mail.promotions.yahoo.com/newdomains/aa/
>
> [Non-text portions of this message have been removed]
>

>

[Non-text portions of this message have been removed]

------------------------------------

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• Zeynep, All the peaks in XPS shifts because of charging effect. It is common in XPS data. They needs to be re-shifted back based on the reference element
Message 3 of 11 , May 11 7:27 PM
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Zeynep,
All the peaks in XPS shifts because of charging effect. It is common in XPS
data. They needs to be re-shifted back based on the reference element before
doing analysis.

Sometimes you may just see one peak, but it may be sum of many small peaks.
I used peakfit software to fit all the individual peaks into XPS data.
Analyzing XPS data looks complicated at first couple of times, but it is
pretty simple afterwards.

Please review section 3.2 in page 3 of the attached publication. (Ce3+ has 4
peaks & Ce4+ has 6 peaks- i mentioned it otherway in my last mail)

Thanks
Ranjith

On Mon, May 11, 2009 at 3:48 PM, zeynep meric <zeyno_ms@...> wrote:

>
>
>
> thanks a lot but this is so complicated than ı expect.ı will try
>
>
>
> ----- Original Message ----
> From: ranjith kumar <ranjith2882@... <ranjith2882%40gmail.com>>
> To: nanotech@yahoogroups.com <nanotech%40yahoogroups.com>
> Sent: Monday, May 11, 2009 5:04:41 PM
> Subject: Re: [nanotech] XPS
>
> Zeynep,
> I extensively used XPS during my masters on nanoceria. Ce can present in
> both Ce3+ and Ce4+. I have total of 10 peaks for Cerium (out of which 6 are
> from Ce3+ and 4 are from Ce4+). To find the Ce3+ to Ce4+ ratio, I
> calculated
> it as a ratio of Area under all the 6 corresponding peaks to Area under 4
> corresponding peaks.
> (All the calculations are based on B.E)
>
> so I suggest, find what are the oxidation states of the element and then
> which peaks corresponds to which oxidation states. Area under the curve is
> the good representation of how much of that state present in it.
>
> XPS is a powerful tool to analyze oxidation states.
>
> Thanks
> Ranjith
>
> >wrote:
>
> >
> >
> > dear different energies corrospond to different elements, if your plot
> have
> > K.E versus Intensity. you have to convert it first into B.E by simple
> > Photoeletric formula, I dont know what was youe exasct question.
> > Regards
> >
> >
> > ________________________________
> >
> > From: zeynep meric <zeyno_ms@... <zeyno_ms%40yahoo.com> <zeyno_ms%
> 40yahoo.com>>
> > To: nanotech@yahoogroups.com <nanotech%40yahoogroups.com> <nanotech%
> 40yahoogroups.com>
>
> > Sent: Monday, May 11, 2009 9:10:10
> > Subject: Re: [nanotech] XPS
> >
> > thanks a lot.
> > but all these Xps handbooks shows diffrent energies for elements.What
> > causes the difference of these energies?
> >
> > ____________ _________ _________ __
> > From: Pankaj Gupta <pankajgupta78@ yahoo.com>
> > To: nanotech@yahoogroup s.com
> > Sent: Monday, May 11, 2009 4:04:03 AM
> > Subject: Re: [nanotech] XPS
> >
> > Zeynep,
> >
> > XPS handbooks are good source of most of the peaks. I am not sure, what
> > material you are working with, but there are some novel peaks, you might
> > have to dig through literature.
> >
> > Thanks
> > Pankaj
> >
> > --- On Sat, 5/9/09, zeynep meric <zeyno_ms@yahoo. com> wrote:
> >
> > From: zeynep meric <zeyno_ms@yahoo. com>
> > Subject: [nanotech] XPS
> > To: nanotech@yahoogroup s.com
> > Date: Saturday, May 9, 2009, 11:20 AM
> >
> > Hello for everyone
> > Is there anybody that know XPS meansX-ray photoelectron spectroscopy.
> > I have data and a graph and ý found out some peak's elemental meaning but
> > stil I am not clear about that.Is there anybody that can explain all
> > peaks?or sent me any book paper or smt else about that.
> >
> > ZEYNEP MERÝÇ
> > (MASTER STUDENT)
> >
> > [Non-text portions of this message have been removed]
> >
> > [Non-text portions of this message have been removed]
> >
> > [Non-text portions of this message have been removed]
> >
> > New Email names for you!
> > Get the Email name you've always wanted on the new @ymail and
> > @rocketmail.
> > Hurry before someone else does!
> > http://mail.promotions.yahoo.com/newdomains/aa/
> >
> > [Non-text portions of this message have been removed]
> >
> >
> >
>
> [Non-text portions of this message have been removed]
>
> ------------------------------------
>
> The Nanotechnology Industries mailing list.
> http://www.nanoindustries.com
> Nanotechnology: solutions for the future.Yahoo! Groups Links
>
>
>

[Non-text portions of this message have been removed]
• who knows mean free path of aluminium oxide?
Message 4 of 11 , May 13 1:30 AM
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who knows mean free path of aluminium oxide?
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