## Re: Vector Space Problem I Need Help

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• While -1 = 1 there are three suspaces: [(1,0)] = {(1,0), (0,0)} [(0,1)] = {(0,1), (0,0)} [(1,1)] = {(1,1), (0,0)} But you are true that it is a
Message 1 of 4232 , Sep 1, 2001
While -1 = 1 there are three suspaces:<br>[(1,0)]
= {(1,0), (0,0)}<br>[(0,1)] = {(0,1),
(0,0)}<br>[(1,1)] = {(1,1), (0,0)}<br>But you are true that it is a
counterexample to the expression [n:k].<br><br>I think that the
number of subspaces should depend not only on n,k but
also on p.<br><br>To my previous message<br>It is
better to consider a set of k independent vectors
instead of the set which contains k ind. vector. <br>Then
you get the reduced triangular matrix with non zero
rows and you don't need to think of deleting zero
rows.<br>I realised it after posting.<br><br>Beata
• can t sleep (yawn), i spent around 3 hr.s on your your original post here. it seems this implicit function solution set is the semi-stable modular eliptical
Message 4232 of 4232 , Apr 25, 2011
can't sleep (yawn), i spent around 3 hr.s on your your original post here. it seems this implicit function solution set is the semi-stable modular eliptical curves A. Wiles gave in his proof of fermat's last theorem. Your function is way simpler. have to get some sleep before i got to go to work, but the proof of this is around 4 to 5 pages as you said. i'll have to look at it more this evening. also, what's the scoop of you being the source for the plot of tron legacy? we should all get royalties! heheh.
--- In mathforfun@yahoogroups.com, jeshields_98 wrote:
>
> I hit the wrong button...<br><br>It should be = c^n<br>not + c^n<br><br>very VEEERRRRRYYYYY important<br><br>sorry
>
I
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