## Re: [lbnews] Mathematician Needed

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• Given N objects from which to select K sets then, the number of combinations = N! / (K! (N - K)!) and the number of permutations = N! / (N - K)! where
Message 1 of 2 , Apr 30, 2001
Given N objects from which to select K sets then,

the number of combinations  = N! / (K! (N - K)!)
and
the number of permutations = N! / (N - K)!

where permutations are those sets where the order of the objects in a set is unique while combinations are the total number of possible sets, regardless of object order.

WDA

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----- Original Message -----
Sent: Sunday, April 29, 2001 8:57 PM
Subject: [lbnews] Mathematician Needed

Does anyone know how to work out permutations?  What I want to do is calculate all the possible permutations of say, 6 numbers out of 7, 8, 9 and so on.  Is there a standard formula or method that will do this?

I can see that you could take the first six numbers and then drop each number in turn, replacing it with one of the extra numbers in sequence, but I how can you be sure that you have covered all possible combinations?

I'm not asking for the Basic code to do this - I can work that out.  What I need is just the method.  Thanks in advance,

Derek

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• NOTICE!!!!!!!!!!! The combination and permutation definitions in my last email are INCORRECT and should be reversed as follows: Combinations = N! / (N-K)! and
Message 2 of 2 , May 1, 2001
NOTICE!!!!!!!!!!!

The combination and permutation definitions in my last email are INCORRECT and should be reversed as follows:

Combinations = N! / (N-K)!

and

Permutations = N! / (K! (N-K)!) =  Combinations / K!

Bill Allen

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----- Original Message -----
Sent: Monday, April 30, 2001 11:15 AM
Subject: [libertybasic] Re: [lbnews] Mathematician Needed

Given N objects from which to select K sets then,

>
> [snipped]
>

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