Re: Why does my Array usage halt jslint
- --- In firstname.lastname@example.org, TIM FULCHER <tfulcher@...> wrote:
> var a = new Array("one","two","three");
> Then jslint indicates the error but then terminates further processing with a
> " reason=Stopping, unable to continue. (49% scanned) " message
> I can appreciate the array definition could be done better but I'm a bit perplexed why lint terminates because of it ???
Smaller, faster, better.
Just fix your code.