2886RE: Changes to the Hardrock qualifications and lottery for 2013
- Jun 24, 2012No Matt, we mean 2^N. So first time applicants get 2^0 = 1 ticket. Those with one DNS get 2^1 = 2 tickets. And so on to those three unfortunate souls who will have 6 DNSs without a DNF or finish, and will get 2^6 = 64 tickets, should they apply again.
From: Matt Mahoney [mattmahoneyfl@...]
> Modeling suggests that giving applicants 2^N tickets, where N is the number of previous DNSs,I think you mean (N)x(N+1)/2 (N tries with N tickets on the N'th try).
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