## Re: [Hammock Camping] Re: Info for the SEHH? Count

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• Nope, not factorial, that would have multiplied 1*2*3*4*5*6 = 120 etc, this was adding, I started down that path also. I also looked at fibbinonci numbers. The
Message 1 of 14 , Feb 25, 2005
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Nope, not factorial, that would have multiplied 1*2*3*4*5*6 = 120 etc,
this was adding, I started down that path also. I also looked at
fibbinonci numbers.

The key is each additional tree, can in theory, hang to all previous trees.

But Coy is right, if two trees are tall enough, everybody could just
stack up there. And Ricks method would double that.

Ralph the midnight mathematician

PS as one who is unlikely to master the mythical bottle. I would need.
ground acess at least twice duting the evening

On Fri, 25 Feb 2005 11:44:47 -0000, J.D. Hoessle <JD@...> wrote:
>
> --- In hammockcamping@yahoogroups.com, Ralph Oborn <Ralph.oborn@g...>
> wrote:
> > If you know the number of trees then you can use the combinatorics
> > function to calculate the number of possible hangers.
>
> Ohhhhh....!!! *THAT's* Good!
>
> Actually, if my ol' brain is working, I think it is a math function
> called a FACTORIAL, right?
>
> Of course, it *IS* limited by the actual emphirical number of trees.
> But, I guess hammocks could be "stacked"; e.g., one at 3 feet and
> another (above) at 6 feet.
>
> Which brings up the subject of who gets the "bottom bunk". With all
> the discussion of technique using the infamous "Pee-Bottle", it would
> be advisable to get there early and claim the top bunk, right?
>
>
>
>
>