Yes and no!

The forces (x and y) do not have to add up to the total force. Sorry

that is just how vectors work. The vertical force on each end are

weight/2 assuming you are right in the middle, but the total load

(tension on the rope) can be many times higher. You are also correct

that this is just the static load, as Dave and others point out

dynamic load while getting in and out may be much higher.

As a thought experiment to understand how the rope tension may be much

higher than the load imaging the empty hammock strung tightly between

two sturdy trees. The vertical load is almost zero, but the almost

horizontal tension may be hundreds of pounds.

Ralph

On Tue, 07 Dec 2004 00:52:00 -0000, jwj32542 <jwj32542@...> wrote:

>

>

> --- In hammockcamping@yahoogroups.com, Ralph Oborn

> <Ralph.oborn@g...> wrote:

> > I took the physics too (actually got the degree) . So when I first

> got

> > on the group I made a spreadsheet (under files) so you can

> calculate

> > the forces.

>

> I'm having a hard time understanding this. The force exerted on a

> hammock line is broken into X and Y components. In a 2D view, the

> sum of X and Y must equal the total force. The vertical forces

> equal weight/2, which makes sense, but in your spreadsheet the total

> forces do not equal X+Y. Why not? Why does that formula apply to

> the horizontal forces?

>

> It's also important to note that those are static calculations. The

> weight of you plopping down into the hammock can result in a dynamic

> force much greater than your weight when lying still.

>

> Jeff

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> Yahoo! Groups Links

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