- The other day I read Youngbloods excellent article on sag angle here:

http://www.hammockcamping.com/Newsletters/2006/Jan2006.htm

Yall are going to have to check my math but if I got it right then to

get the 30deg sag angle, all you need to do is hang the hammock taut

and then let out another 10-15% rope/webbing to get 30 deg. I suppose

if you wanted to get real precise you could mark the webbing/rope in a

manner that would let you guesstimate better. And this is without a

ridgeline of course.

Now for the geeky stuff.

In the paper he had 15 deg and 30 deg. I'll include 0 deg just for reference.

Cos (0 deg) = 1

Cos (15 deg) = .965

Cos (30 deg_ = .866

To get the length of rop

Cos (30 deg) = distance from tree (x) / length of rope (y)

to solve for y = x / 0.866

or just the inverse of the angle's cosine (when comparing it to the 0

Deg, nominal value of 1)

if you take the inverse of those numbers you get

1/ Cos( 0 deg )= 1

1/ Cos (15 deg )= 1.036

1/ Cos (30 deg) = 1.155

So basically what that means is if the hammock line is perfectly flat

it will have a nominal value of 1 and at 30 deg it is ~15% longer

1.155. So if your hammock was lying flat on the ground and the

distance from the hammock to the tree was 4 ft, then you would need

4.6ft ( 4 * 1.155) of distance to get 30 deg sag angle. If you have

it hung taut it probably isn't going to be at 0 deg so let's just use

15 deg. Then the nominal value is 1.036. To get the needed distance to

hang at 30 deg it's about ~10% longer than when hung taut.

So my first question is, does that make sense? :)

Second question is, am I correct? :))

Scott - Scott... it sounds right to me. I think you can get an unloaded

hammock hanging pretty close to the horizon if you tie it taut, close

enough to not worry about compensating for it.

Dave Womble

aka Youngblood

--- In hammockcamping@yahoogroups.com, "Scott Schroeder"

<schrochem@...> wrote:>

reference.

> The other day I read Youngbloods excellent article on sag angle here:

> http://www.hammockcamping.com/Newsletters/2006/Jan2006.htm

>

> Yall are going to have to check my math but if I got it right then to

> get the 30deg sag angle, all you need to do is hang the hammock taut

> and then let out another 10-15% rope/webbing to get 30 deg. I suppose

> if you wanted to get real precise you could mark the webbing/rope in a

> manner that would let you guesstimate better. And this is without a

> ridgeline of course.

>

> Now for the geeky stuff.

> In the paper he had 15 deg and 30 deg. I'll include 0 deg just for

> Cos (0 deg) = 1

> Cos (15 deg) = .965

> Cos (30 deg_ = .866

>

> To get the length of rop

>

> Cos (30 deg) = distance from tree (x) / length of rope (y)

> to solve for y = x / 0.866

> or just the inverse of the angle's cosine (when comparing it to the 0

> Deg, nominal value of 1)

>

> if you take the inverse of those numbers you get

> 1/ Cos( 0 deg )= 1

> 1/ Cos (15 deg )= 1.036

> 1/ Cos (30 deg) = 1.155

>

> So basically what that means is if the hammock line is perfectly flat

> it will have a nominal value of 1 and at 30 deg it is ~15% longer

> 1.155. So if your hammock was lying flat on the ground and the

> distance from the hammock to the tree was 4 ft, then you would need

> 4.6ft ( 4 * 1.155) of distance to get 30 deg sag angle. If you have

> it hung taut it probably isn't going to be at 0 deg so let's just use

> 15 deg. Then the nominal value is 1.036. To get the needed distance to

> hang at 30 deg it's about ~10% longer than when hung taut.

>

> So my first question is, does that make sense? :)

> Second question is, am I correct? :))

>

> Scott

> - Opps... after I posted that message I thought about the hammock

itself. Your method works if the hammock has a structural ridgeline

but a hammock with a non-structural ridgeline would be a problem

because you would want its length to be increased by the same 1.15

ratio, wouldn't you?

Without the structural ridgeline you would have to add another math

step, where you added half the difference of the length of the 0 sag

angle hammock and the 30 degree sag angle hammock to each suspension

line before you multiply the 1.15 ratio to the rope... I think.

Dave

--- In hammockcamping@yahoogroups.com, "Dave Womble" <dpwomble@...> wrote:

>

> Scott... it sounds right to me. I think you can get an unloaded

> hammock hanging pretty close to the horizon if you tie it taut, close

> enough to not worry about compensating for it.

>

> Dave Womble

> aka Youngblood

>

> --- In hammockcamping@yahoogroups.com, "Scott Schroeder"

> <schrochem@> wrote:

> >

> > The other day I read Youngbloods excellent article on sag angle here:

> > http://www.hammockcamping.com/Newsletters/2006/Jan2006.htm

> >

> > Yall are going to have to check my math but if I got it right then to

> > get the 30deg sag angle, all you need to do is hang the hammock taut

> > and then let out another 10-15% rope/webbing to get 30 deg. I suppose

> > if you wanted to get real precise you could mark the webbing/rope in a

> > manner that would let you guesstimate better. And this is without a

> > ridgeline of course.

> >

> > Now for the geeky stuff.

> > In the paper he had 15 deg and 30 deg. I'll include 0 deg just for

> reference.

> > Cos (0 deg) = 1

> > Cos (15 deg) = .965

> > Cos (30 deg_ = .866

> >

> > To get the length of rop

> >

> > Cos (30 deg) = distance from tree (x) / length of rope (y)

> > to solve for y = x / 0.866

> > or just the inverse of the angle's cosine (when comparing it to the 0

> > Deg, nominal value of 1)

> >

> > if you take the inverse of those numbers you get

> > 1/ Cos( 0 deg )= 1

> > 1/ Cos (15 deg )= 1.036

> > 1/ Cos (30 deg) = 1.155

> >

> > So basically what that means is if the hammock line is perfectly flat

> > it will have a nominal value of 1 and at 30 deg it is ~15% longer

> > 1.155. So if your hammock was lying flat on the ground and the

> > distance from the hammock to the tree was 4 ft, then you would need

> > 4.6ft ( 4 * 1.155) of distance to get 30 deg sag angle. If you have

> > it hung taut it probably isn't going to be at 0 deg so let's just use

> > 15 deg. Then the nominal value is 1.036. To get the needed distance to

> > hang at 30 deg it's about ~10% longer than when hung taut.

> >

> > So my first question is, does that make sense? :)

> > Second question is, am I correct? :))

> >

> > Scott

> >

>