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Re: [hameltech] Re: Need help on pyramid construction...

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  • Timothy
    90 ??? why 90??? what are you trying to build??? Hmmmm... maybe this might help??? http://46.1911encyclopedia.org/P/PO/POLYHEDRON.htm Timothy... ...
    Message 1 of 11 , Jan 2, 2005
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      90'???
      why 90???
      what are you trying to build???
      Hmmmm...
      maybe this might help???
      http://46.1911encyclopedia.org/P/PO/POLYHEDRON.htm

      Timothy...

      --- cirrex2001 <meissner@...> wrote:

      >
      > Ok good people,but I can't take four 90 degree
      > triangles and glue
      > them together...I will obtain a perfect flat
      > square in this manner!
      >
      > P.S:Happay new 2005!
      >
      > Cyrano.
      >
      >
      >
      >
      > --- In hameltech@yahoogroups.com, Timothy
      > <flytch@y...> wrote:
      > > DC... your over thinking the problem...
      > > Timothy...
      > >
      > > --- Dell Coleman <decoleman@p...> wrote:
      > >
      > > > Hi
      > > >
      > > > Just to be clear sin(60) is 0.8660254
      > and
      > > > 60*0.8660254 = 51.961524
      > > >
      > > > DC
      > > >
      > > >
      > > > Dell Coleman wrote:
      > > >
      > > > > Hi
      > > > > I think there is more to it .. If you
      > want
      > > > to build a four sided
      > > > > pyramid of equilateral triangles, you
      > need to
      > > > know a bit of trig or
      > > > > figure it out.
      > > > > If I make four equilateral triangles, one
      > on
      > > > each side, I dont have a
      > > > > pyramid I have four toast-points and an
      > open
      > > > roof. What angle then do
      > > > > I need to lay the triangles back to close
      > the
      > > > roof? The angles of
      > > > > the triangle are all 60 degrees and the
      > > > answer is Sin(60)
      > > > > Also, you dont need to buld a monster
      > pyramid
      > > > to figure this out. If I
      > > > > make a set of cardboard equilateral
      > triangles
      > > > and lay them back, they
      > > > > will achieve sin(60). If I make a
      > template
      > > > and mark the angle, then I
      > > > > can use it on any further equilateral
      > > > pryamids.
      > > > >
      > > > > DC
      > > > >
      > > > > Timothy wrote:
      > > > >
      > > > >> this has already been worked out... if
      > you
      > > > simply
      > > > >> use a wheel to lay out your dimensions
      > you
      > > > get
      > > > >> this layout plain and simple... no high
      > tech
      > > > >> here... not even an understanding of the
      > > > math...
      > > > >> it is just a one two arrangement...
      > > > >> Timothy...
      > > > >>
      > > > >> --- brian jewell <creationvger@y...>
      > > > wrote:
      > > > >>
      > > > >> > I'm not sure what you mean; but the
      > > > beginning
      > > > >> > of the formula to the great pyramid of
      > > > Giza is:
      > > > >> > height times 1/2 Pi = width. The Great
      > > > pyramid
      > > > >> > is an exact sphere mathmatically
      > turned
      > > > inside
      > > > >> > out. There are about 24 equasions to
      > the
      > > > >> > formula for the building of 1 basic
      > > > pyramid
      > > > >> > model. You may write me personally to
      > > > discuss
      > > > >> > this. It may help to tell me something
      > > > about
      > > > >> > what you are after.
      > > > >> >
      > > > >> > cirrex2001 <meissner@t...> wrote:
      > > > >> > Hello to all!
      > > > >> > I need to build a model of a pyramid
      > with
      > > > 90
      > > > >> > degree apex.Someone can
      > > > >> > suggest some formulas for it?
      > > > >> > Lot of thanks.
      > > > >> >
      > > > >> > Regards,
      > > > >> > Cyrano
      > > > >> >
      > > > >> >
      > > > >> >
      > > > >> >
      > > > >> >
      > > > >> > Header Codes
      > > > >> > 11111: Theory, untested Hamel ideas
      > > > >> > 11112: Building and balancing,
      > progress
      > > > >> > 11113: David Hamel reports
      > > > >> > 11114: Non-hamel mysteries and
      > energies
      > > > >> > OT: "Off Topic"
      > > > >> >
      > > > >> > Post message:
      > hameltech@yahoogroups.com
      > > > >> > Subscribe:
      > > > hameltech-subscribe@yahoogroups.com
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      > > > >>
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      > > > >
      > > > >
      > > > >
      > > > > Header Codes
      > > > > 11111: Theory, untested Hamel ideas
      > > > > 11112: Building and balancing, progress
      > > > > 11113: David Hamel reports
      > > > > 11114: Non-hamel mysteries and energies
      > > > > OT: "Off Topic"
      > > > >
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      >
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      > 6/*http://companion.yahoo.com>
      > > >
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      > > > >
      > > > >
      > > > >
      > > >
      > >
      >
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    • Matt Rock
      Hi Cyrano, The Great Pyramid is 1.618 on it side/face while looking at it horizantally. The Height being 1.272. Then the base of one side is about 2. So to
      Message 2 of 11 , Jan 3, 2005
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        Hi Cyrano,

        The Great Pyramid is 1.618 on it side/face while looking at it
        horizantally. The Height being 1.272. Then the base of one side is
        about 2.

        So to recreate, make a triangle which has about 2 on base. 1.618 from
        base to apex and using your Pythagorean knowledge for a right hand
        triangle, figure out your slopes for each triangle.
        Which in this case would be. Z= ((1.618)^2 + (1)^2))^1/2
        .....1.9........

        Base=2
        height=1.618
        slope=1.9......

        Matt


        --- In hameltech@yahoogroups.com, "cirrex2001" <meissner@t...> wrote:
        >
        > Ok good people,but I can't take four 90 degree triangles and glue
        > them together...I will obtain a perfect flat square in this manner!
        >
        > P.S:Happay new 2005!
        >
        > Cyrano.
        >
        >
        >
        >
        > --- In hameltech@yahoogroups.com, Timothy <flytch@y...> wrote:
        > > DC... your over thinking the problem...
        > > Timothy...
        > >
        > > --- Dell Coleman <decoleman@p...> wrote:
        > >
        > > > Hi
        > > >
        > > > Just to be clear sin(60) is 0.8660254 and
        > > > 60*0.8660254 = 51.961524
        > > >
        > > > DC
        > > >
        > > >
        > > > Dell Coleman wrote:
        > > >
        > > > > Hi
        > > > > I think there is more to it .. If you want
        > > > to build a four sided
        > > > > pyramid of equilateral triangles, you need to
        > > > know a bit of trig or
        > > > > figure it out.
        > > > > If I make four equilateral triangles, one on
        > > > each side, I dont have a
        > > > > pyramid I have four toast-points and an open
        > > > roof. What angle then do
        > > > > I need to lay the triangles back to close the
        > > > roof? The angles of
        > > > > the triangle are all 60 degrees and the
        > > > answer is Sin(60)
        > > > > Also, you dont need to buld a monster pyramid
        > > > to figure this out. If I
        > > > > make a set of cardboard equilateral triangles
        > > > and lay them back, they
        > > > > will achieve sin(60). If I make a template
        > > > and mark the angle, then I
        > > > > can use it on any further equilateral
        > > > pryamids.
        > > > >
        > > > > DC
        > > > >
        > > > > Timothy wrote:
        > > > >
        > > > >> this has already been worked out... if you
        > > > simply
        > > > >> use a wheel to lay out your dimensions you
        > > > get
        > > > >> this layout plain and simple... no high tech
        > > > >> here... not even an understanding of the
        > > > math...
        > > > >> it is just a one two arrangement...
        > > > >> Timothy...
        > > > >>
        > > > >> --- brian jewell <creationvger@y...>
        > > > wrote:
        > > > >>
        > > > >> > I'm not sure what you mean; but the
        > > > beginning
        > > > >> > of the formula to the great pyramid of
        > > > Giza is:
        > > > >> > height times 1/2 Pi = width. The Great
        > > > pyramid
        > > > >> > is an exact sphere mathmatically turned
        > > > inside
        > > > >> > out. There are about 24 equasions to the
        > > > >> > formula for the building of 1 basic
        > > > pyramid
        > > > >> > model. You may write me personally to
        > > > discuss
        > > > >> > this. It may help to tell me something
        > > > about
        > > > >> > what you are after.
        > > > >> >
        > > > >> > cirrex2001 <meissner@t...> wrote:
        > > > >> > Hello to all!
        > > > >> > I need to build a model of a pyramid with
        > > > 90
        > > > >> > degree apex.Someone can
        > > > >> > suggest some formulas for it?
        > > > >> > Lot of thanks.
        > > > >> >
        > > > >> > Regards,
        > > > >> > Cyrano
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> > Header Codes
        > > > >> > 11111: Theory, untested Hamel ideas
        > > > >> > 11112: Building and balancing, progress
        > > > >> > 11113: David Hamel reports
        > > > >> > 11114: Non-hamel mysteries and energies
        > > > >> > OT: "Off Topic"
        > > > >> >
        > > > >> > Post message: hameltech@yahoogroups.com
        > > > >> > Subscribe:
        > > > hameltech-subscribe@yahoogroups.com
        > > > >> >
        > > > >> > Unsubscribe:
        > > > >> > hameltech-unsubscribe@yahoogroups.com
        > > > >> > List owner:
        > > > hameltech-owner@yahoogroups.com
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> > Yahoo! Groups SponsorADVERTISEMENT
        > > > >> >
        > > > >> >
        > > > >> > ---------------------------------
        > > > >> > Yahoo! Groups Links
        > > > >> >
        > > > >> > To visit your group on the web, go to:
        > > > >> > http://groups.yahoo.com/group/hameltech/
        > > > >> >
        > > > >> > To unsubscribe from this group, send an
        > > > >> > email to:
        > > > >> > hameltech-unsubscribe@yahoogroups.com
        > > > >> >
        > > > >> > Your use of Yahoo! Groups is subject to
        > > > the
        > > > >> > Yahoo! Terms of Service.
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >> >
        > > > >>
        > > >
        > > __________________________________________________
        > > > >> > Do You Yahoo!?
        > > > >> > Tired of spam? Yahoo! Mail has the best
        > > > spam
        > > > >> > protection around
        > > > >> > http://mail.yahoo.com
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        > > > >>
        > > > >>
        > > > >>
        > > > >> __________________________________
        > > > >> Do you Yahoo!?
        > > > >> Dress up your holiday email, Hollywood
        > > > style. Learn more.
        > > > >> http://celebrity.mail.yahoo.com
        > > > >>
        > > > >>
        > > > >> Header Codes
        > > > >> 11111: Theory, untested Hamel ideas
        > > > >> 11112: Building and balancing, progress
        > > > >> 11113: David Hamel reports
        > > > >> 11114: Non-hamel mysteries and energies
        > > > >> OT: "Off Topic"
        > > > >>
        > > > >> Post message: hameltech@yahoogroups.com
        > > > >> Subscribe:
        > > > hameltech-subscribe@yahoogroups.com
        > > > >> Unsubscribe:
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        > > > >> List owner: hameltech-owner@yahoogroups.com
        > > > >>
        > > > >>
        > > > >>
        > > > >
        > > > >
        > > > >
        > > > > Header Codes
        > > > > 11111: Theory, untested Hamel ideas
        > > > > 11112: Building and balancing, progress
        > > > > 11113: David Hamel reports
        > > > > 11114: Non-hamel mysteries and energies
        > > > > OT: "Off Topic"
        > > > >
        > > > > Post message: hameltech@yahoogroups.com
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        > > >
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