## Re: [hameltech] Re: Need help on pyramid construction...

Expand Messages
• 90 ??? why 90??? what are you trying to build??? Hmmmm... maybe this might help??? http://46.1911encyclopedia.org/P/PO/POLYHEDRON.htm Timothy... ...
Message 1 of 11 , Jan 2, 2005
90'???
why 90???
what are you trying to build???
Hmmmm...
maybe this might help???
http://46.1911encyclopedia.org/P/PO/POLYHEDRON.htm

Timothy...

--- cirrex2001 <meissner@...> wrote:

>
> Ok good people,but I can't take four 90 degree
> triangles and glue
> them together...I will obtain a perfect flat
> square in this manner!
>
> P.S:Happay new 2005!
>
> Cyrano.
>
>
>
>
> --- In hameltech@yahoogroups.com, Timothy
> <flytch@y...> wrote:
> > DC... your over thinking the problem...
> > Timothy...
> >
> > --- Dell Coleman <decoleman@p...> wrote:
> >
> > > Hi
> > >
> > > Just to be clear sin(60) is 0.8660254
> and
> > > 60*0.8660254 = 51.961524
> > >
> > > DC
> > >
> > >
> > > Dell Coleman wrote:
> > >
> > > > Hi
> > > > I think there is more to it .. If you
> want
> > > to build a four sided
> > > > pyramid of equilateral triangles, you
> need to
> > > know a bit of trig or
> > > > figure it out.
> > > > If I make four equilateral triangles, one
> on
> > > each side, I dont have a
> > > > pyramid I have four toast-points and an
> open
> > > roof. What angle then do
> > > > I need to lay the triangles back to close
> the
> > > roof? The angles of
> > > > the triangle are all 60 degrees and the
> > > answer is Sin(60)
> > > > Also, you dont need to buld a monster
> pyramid
> > > to figure this out. If I
> > > > make a set of cardboard equilateral
> triangles
> > > and lay them back, they
> > > > will achieve sin(60). If I make a
> template
> > > and mark the angle, then I
> > > > can use it on any further equilateral
> > > pryamids.
> > > >
> > > > DC
> > > >
> > > > Timothy wrote:
> > > >
> > > >> this has already been worked out... if
> you
> > > simply
> > > >> use a wheel to lay out your dimensions
> you
> > > get
> > > >> this layout plain and simple... no high
> tech
> > > >> here... not even an understanding of the
> > > math...
> > > >> it is just a one two arrangement...
> > > >> Timothy...
> > > >>
> > > >> --- brian jewell <creationvger@y...>
> > > wrote:
> > > >>
> > > >> > I'm not sure what you mean; but the
> > > beginning
> > > >> > of the formula to the great pyramid of
> > > Giza is:
> > > >> > height times 1/2 Pi = width. The Great
> > > pyramid
> > > >> > is an exact sphere mathmatically
> turned
> > > inside
> > > >> > out. There are about 24 equasions to
> the
> > > >> > formula for the building of 1 basic
> > > pyramid
> > > >> > model. You may write me personally to
> > > discuss
> > > >> > this. It may help to tell me something
> > > >> > what you are after.
> > > >> >
> > > >> > cirrex2001 <meissner@t...> wrote:
> > > >> > Hello to all!
> > > >> > I need to build a model of a pyramid
> with
> > > 90
> > > >> > degree apex.Someone can
> > > >> > suggest some formulas for it?
> > > >> > Lot of thanks.
> > > >> >
> > > >> > Regards,
> > > >> > Cyrano
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> > Header Codes
> > > >> > 11111: Theory, untested Hamel ideas
> > > >> > 11112: Building and balancing,
> progress
> > > >> > 11113: David Hamel reports
> > > >> > 11114: Non-hamel mysteries and
> energies
> > > >> > OT: "Off Topic"
> > > >> >
> > > >> > Post message:
> hameltech@yahoogroups.com
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> > > >> >
> > > >> >
> > > >> >
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> > > >> 11113: David Hamel reports
> > > >> 11114: Non-hamel mysteries and energies
> > > >> OT: "Off Topic"
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> > > >
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> > > > Header Codes
> > > > 11111: Theory, untested Hamel ideas
> > > > 11112: Building and balancing, progress
> > > > 11113: David Hamel reports
> > > > 11114: Non-hamel mysteries and energies
> > > > OT: "Off Topic"
> > > >
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• Hi Cyrano, The Great Pyramid is 1.618 on it side/face while looking at it horizantally. The Height being 1.272. Then the base of one side is about 2. So to
Message 2 of 11 , Jan 3, 2005
Hi Cyrano,

The Great Pyramid is 1.618 on it side/face while looking at it
horizantally. The Height being 1.272. Then the base of one side is

So to recreate, make a triangle which has about 2 on base. 1.618 from
base to apex and using your Pythagorean knowledge for a right hand
triangle, figure out your slopes for each triangle.
Which in this case would be. Z= ((1.618)^2 + (1)^2))^1/2
.....1.9........

Base=2
height=1.618
slope=1.9......

Matt

--- In hameltech@yahoogroups.com, "cirrex2001" <meissner@t...> wrote:
>
> Ok good people,but I can't take four 90 degree triangles and glue
> them together...I will obtain a perfect flat square in this manner!
>
> P.S:Happay new 2005!
>
> Cyrano.
>
>
>
>
> --- In hameltech@yahoogroups.com, Timothy <flytch@y...> wrote:
> > DC... your over thinking the problem...
> > Timothy...
> >
> > --- Dell Coleman <decoleman@p...> wrote:
> >
> > > Hi
> > >
> > > Just to be clear sin(60) is 0.8660254 and
> > > 60*0.8660254 = 51.961524
> > >
> > > DC
> > >
> > >
> > > Dell Coleman wrote:
> > >
> > > > Hi
> > > > I think there is more to it .. If you want
> > > to build a four sided
> > > > pyramid of equilateral triangles, you need to
> > > know a bit of trig or
> > > > figure it out.
> > > > If I make four equilateral triangles, one on
> > > each side, I dont have a
> > > > pyramid I have four toast-points and an open
> > > roof. What angle then do
> > > > I need to lay the triangles back to close the
> > > roof? The angles of
> > > > the triangle are all 60 degrees and the
> > > answer is Sin(60)
> > > > Also, you dont need to buld a monster pyramid
> > > to figure this out. If I
> > > > make a set of cardboard equilateral triangles
> > > and lay them back, they
> > > > will achieve sin(60). If I make a template
> > > and mark the angle, then I
> > > > can use it on any further equilateral
> > > pryamids.
> > > >
> > > > DC
> > > >
> > > > Timothy wrote:
> > > >
> > > >> this has already been worked out... if you
> > > simply
> > > >> use a wheel to lay out your dimensions you
> > > get
> > > >> this layout plain and simple... no high tech
> > > >> here... not even an understanding of the
> > > math...
> > > >> it is just a one two arrangement...
> > > >> Timothy...
> > > >>
> > > >> --- brian jewell <creationvger@y...>
> > > wrote:
> > > >>
> > > >> > I'm not sure what you mean; but the
> > > beginning
> > > >> > of the formula to the great pyramid of
> > > Giza is:
> > > >> > height times 1/2 Pi = width. The Great
> > > pyramid
> > > >> > is an exact sphere mathmatically turned
> > > inside
> > > >> > out. There are about 24 equasions to the
> > > >> > formula for the building of 1 basic
> > > pyramid
> > > >> > model. You may write me personally to
> > > discuss
> > > >> > this. It may help to tell me something
> > > >> > what you are after.
> > > >> >
> > > >> > cirrex2001 <meissner@t...> wrote:
> > > >> > Hello to all!
> > > >> > I need to build a model of a pyramid with
> > > 90
> > > >> > degree apex.Someone can
> > > >> > suggest some formulas for it?
> > > >> > Lot of thanks.
> > > >> >
> > > >> > Regards,
> > > >> > Cyrano
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> > Header Codes
> > > >> > 11111: Theory, untested Hamel ideas
> > > >> > 11112: Building and balancing, progress
> > > >> > 11113: David Hamel reports
> > > >> > 11114: Non-hamel mysteries and energies
> > > >> > OT: "Off Topic"
> > > >> >
> > > >> > Post message: hameltech@yahoogroups.com
> > > >> > Subscribe:
> > > hameltech-subscribe@yahoogroups.com
> > > >> >
> > > >> > Unsubscribe:
> > > >> > hameltech-unsubscribe@yahoogroups.com
> > > >> > List owner:
> > > hameltech-owner@yahoogroups.com
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> > ---------------------------------
> > > >> > Yahoo! Groups Links
> > > >> >
> > > >> > To visit your group on the web, go to:
> > > >> > http://groups.yahoo.com/group/hameltech/
> > > >> >
> > > >> > To unsubscribe from this group, send an
> > > >> > email to:
> > > >> > hameltech-unsubscribe@yahoogroups.com
> > > >> >
> > > >> > Your use of Yahoo! Groups is subject to
> > > the
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >> >
> > > >>
> > >
> > __________________________________________________
> > > >> > Do You Yahoo!?
> > > >> > Tired of spam? Yahoo! Mail has the best
> > > spam
> > > >> > protection around
> > > >> > http://mail.yahoo.com
> > > >>
> > > >>
> > > >>
> > > >>
> > > >> __________________________________
> > > >> Do you Yahoo!?
> > > >> Dress up your holiday email, Hollywood
> > > >> http://celebrity.mail.yahoo.com
> > > >>
> > > >>
> > > >> Header Codes
> > > >> 11111: Theory, untested Hamel ideas
> > > >> 11112: Building and balancing, progress
> > > >> 11113: David Hamel reports
> > > >> 11114: Non-hamel mysteries and energies
> > > >> OT: "Off Topic"
> > > >>
> > > >> Post message: hameltech@yahoogroups.com
> > > >> Subscribe:
> > > hameltech-subscribe@yahoogroups.com
> > > >> Unsubscribe:
> > > hameltech-unsubscribe@yahoogroups.com
> > > >> List owner: hameltech-owner@yahoogroups.com
> > > >>
> > > >>
> > > >>
> > > >
> > > >
> > > >
> > > > Header Codes
> > > > 11111: Theory, untested Hamel ideas
> > > > 11112: Building and balancing, progress
> > > > 11113: David Hamel reports
> > > > 11114: Non-hamel mysteries and energies
> > > > OT: "Off Topic"
> > > >
> > > > Post message: hameltech@yahoogroups.com
> > > > Subscribe:
> > > hameltech-subscribe@yahoogroups.com
> > > > Unsubscribe:
> > > hameltech-unsubscribe@yahoogroups.com
> > > > List owner: hameltech-owner@yahoogroups.com
> > > >
> > > >
> > > >
> > > > *Yahoo! Groups Sponsor*
> > > >
> > >
> >
>
<http://us.ard.yahoo.com/SIG=129ibc967/M=295196.4901138.6071305.30011
>
76/D=groups/S=1707208735:HM/EXP=1104530089/A=2128215/R=0/SIG=10se96mf
> 6/*http://companion.yahoo.com>
> > >
> > > >
> > > >
> > > >
> > > >
> > >
> > ------------------------------------------------------------------
-
> -----
> > > > *Yahoo! Groups Links*
> > > >
> > > > * To visit your group on the web, go to:
> > > >
> > > http://groups.yahoo.com/group/hameltech/
> > > >
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> > > >
> > >
> > >
> >
> >
> >
> >
> > __________________________________
> > Do you Yahoo!?
> > Yahoo! Mail - Find what you need with new enhanced search.
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