- Feb 25, 2010Let's imagine that. An isolated system has infinite line of billiard balls. Each previous

ball transfer whole it's own linear momentum to the next ball through a collision action.

However, this next ball takes a hit away from his center of mass.(i.e. each next ball

conducts rotational and translational motion.) Base on law of momentum conservation the last

ball must take same linear momentum as a first ball on this line. However all balls start

rotating on this line. It means, an isolated system with infinite line of balls will grow

own energy to infinite value. If transfer all rotational kinetic energy of these balls to

heat then this isolated system is unlimited power source.

This is nonsense. This should not be happen in reality.

It means,the rotational and translational motion transfer has a different behavior than

translational motion.

This essay is describe this problem and confirm a new theory with an experiment.

http://knol.google.com/k/paradox-of-classical-mechanics-2#

Alex

--- In gravitationalpropulsionstevenson@yahoogroups.com, "abelov0927" <abelov0927@...> wrote:

>

> George.

> Thank you for your peer review.

> However, I think this effect might be to little for this experiment. The

> electric current resistance of this graphite core has a big value.

>

> I made some changes on my site and this may be better helps to

> understand and experiment result. Feel free to comment this.

>

> <http://knol.google.com/k/paradox-of-classical-mechanics-2#>

> http://knol.google.com/k/paradox-of-classical-mechanics-2#

> <http://http://knol.google.com/k/paradox-of-classical-mechanics-2#>

>

> Thank you.

>

> Alex

>

> Newton's First Law: "An object in motion will stay in motion and an

> object at rest will stay at rest unless acted upon by an external force"

> or "A body persists in a state of uniform motion or of rest unless acted

> upon by an external force."

> <http://en.wikipedia.org/wiki/Newton%27s_laws_of_motion>

>

> To use Newton's laws need to simplify each body of experiment to single

> point object. Then these equations should apply for modeling these

> experiments. However, real body's are not single point objects.

>

> To use Newton's mechanic equations for one type of motion, single event

> can not induce two different movements in a single object. One event can

> trigger only one kind of movement in each object. To describe a few

> motions into one single object base on first Newton's law require one

> unique event for each motion. Because an object should stay in one

> motion (First Newton's Law). Not in many motions.

>

> The Newton's mechanic has two types of motions. Rotation and Translation

> motions. Each of these motions has it's own law of momentum

> conservation.

>

> The first experiment conforms to this rule, as there is only one

> translational movement that is induced. These cylinders have repulsive

> action aligned from their center of mass and each cylinder of this

> experiment congruent to single point object. All pieces of these

> cylinders conducts identical uniform motion.

>

> In the second experiment, one of these cylinders have repulsive action

> aligned away from his center mass. Each piece of this cylinder conducts

> it's own cycloidal motion with own trajectory. To simplify this cylinder

> to single point object require to split cycloidal motion to two motions.

> Rotation and translation motions. In this case, following first Newton's

> law repulsive event should split to two independent events. Base on

> this event splitting, the initial force should split to two independent

> forces. Sum of these forces should be equal to initial force. Equations

> with these forces will cover rotation and translation motions for one

> object.

>

> [\{ \vec F_n = \vec F_1+\vec F_2 \\ \vec F_1\times t_1=m\times \vec v

> \\ \\ F_2 \times t_2 \times R = I \times \omega]

>

> Where: Fn -net force for one event F1,F2 - sub forces for each event

> t1,t2 - sub forces action time m - mass of object R - radius I -

> moment of inertia of object v - translation velocity of object w -

> angular velocity of object.

>

> However, to keep situation where one cylinder exhibits translation and

> rotational movements for one event. These two movements are thus

> considered as new type of movements. These movements are hence

> standalone natural phenomenon. So it follows, the movement should have

> its momentum and follow its own conservation of momentum.

> Assuming the movement has a linear and angular momentum, the total

> momentum of rotation with translation movement is:

> [P_f= \sum P_j +\frac{1}{R_u}[\sum L_k]]

> Where, Pj - linear momentum Lk - angular momentum Ru - unit radius

>

> The law of conservation of momentum for the translation movement with

> rotation is:

>

> [\sum P_j +\frac{1}{R_u}[\sum L_k] = Const]

>

>

>

> --- In gravitationalpropulsionstevenson@yahoogroups.com,

> "cambridgephysics" <hubrotherfour@> wrote:

> >

> >

> > Hi,

> >

> > I was considering the compressive nature of wood in conjunction

> with

> > the pencils' hexagonal shape. Each edge of the hexagonal shape would

> > possibly impart additional "bump" motion. Also some consideration of

> > graphite core of pencil might show electromechanical static behavior

> > when in motion next to another like object. Also considered a glass

> rod,

> > but again static electricity might alter behavior. Steel rods could

> > impart a magnetic effect as well. In no way have I reviewed all

> possible

> > conflicts using copper rods, they are after all able to transmit

> > electricity. Just some thoughts really, not derailing the experiment,

> > just thought some more expanded results would help bolster your theory

> > under peer review.

> >

> > Cheers,

> >

> > George

> >

> >

> > --- In gravitationalpropulsionstevenson@yahoogroups.com, Alex Belov

> > abelov0927@ wrote:

> >

> > Hi.

> >

> > How it could be change result?

> >

> > Anyway.

> > Base on law of momentum conservation P=cosnt and momentum equation

> > P=mv, the translation velocity of objects with identical mass must

> have

> > identical value and opposite direction. This law of momentum

> > conservation for objects which conduct translation motions only.

> >

> > However one of these objects conduct rotation and translation motion

> > together. This is a standalone phenomenon.

> > However classical with own law of momentum conservation. However, the

> > modern classical mechanic has rotation and translation motions only.

> > With their own law of momentum conservation.

> >

> > Main Idea of this experiment was show the rotation with translation

> > motion as a standalone natural phenomenon with own law of momentum

> > conservation. This motion should be included into classical mechanics

> > book.

> >

> > Thank you

> >

> > Alex

> >

> >

> >

> >

> > --- On Thu, 2/4/10, cambridgephysics hubrotherfour@ wrote:

> >

> > From: cambridgephysics hubrotherfour@

> > Subject: Gravitational Propulsion, Re: Please take a look on my

> theory

> > To: gravitationalpropulsionstevenson@yahoogroups.com

> > Date: Thursday, February 4, 2010, 9:37 PM

> >

> > Â

> >

> >

> > Hi, Â Â I tried to respond earlier to this experiment but must

> > have made an error in posting.

> > My question has to do with the use of perhaps a round copper rod

> instead

> > of a pencil in performing this experiment? This regards physical

> > properties that may influence results.

> > Â Have you any results using anything other than pencils?

> > Thankyou,

> > George

> >

> > --- In gravitationalpropul sionstevenson@ yahoogroups. com,

> "abelov0927"

> > abelov0927@ ..> wrote:

> > Â Hi.

> > Please take a look on my site.

> > http://knol. google.com/ k/paradox- of-classical- mechanics- 2

> > Â This site contains theory, simulation and real experiment.

> > Â The real experiment proves this theory.

> > Â However, to prove this theory this experiment should be repeated

> > many times by other research groups.

> > Â

> > Please read it and feel free to comment it.

> > Â

> > Thank You.

> >

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