Sorry, an error occurred while loading the content.

## Re: [Fwd: [caostheory] A new kind of periodic catenoid minimal surface tan(3*z)]

Expand Messages
• Dear Dr. Gollek, Thank you very much for your answer and your work. I admire your work and reading your papers has taught me a lot about the importance and
Message 1 of 1 , Mar 4 7:09 AM
Dear Dr. Gollek,
Thank you very much for your answer and your work.

and reading your papers has taught me a lot about the importance
and equations of minimal surfaces. The German school of Minimal surfaces

with Karcher, Webber and Gollek is truly a great one.

I believe I have developed a kind of generalized catenoid formula.
Since, the Tan(n*z) I have found several other catenoid types that are
periodic as well:
(f,g)=(1/Cos[n*z]^2,Cos[n*z]) : sets of even holes
(f,g)=(1/Sin[n*z]^2,Sin[n*z]) : sets of odd holes
and on that this polynomial derivative like:
(f,g)=( (n!)^2/x^(2*n),x^n/n!)
You may enjoy experimenting with these as I have.
Without Mathematica I would never have been able to see these surfaces.

I also developed a four dimensional catenoid formula
and used it to form a three dimensional projection.
If you liked the other result , this should also make you happy.
I started out trying to figure out how to make
minimal surfaces that were simple, that had n ( 0r 2*n) holes in them.
I got that as you have seen.
I'm ,now, working on seeing if I can get higher dimensional catenoid/
helicoids that can
be projected onto three dimensions as I did with the four space.
I used Peter Hennes' 6 space minimal surfaces to get a Hopf 6 map type
last night:
( I believe this is an SO(6) symmetry)
f1=-f2
g1=-I*g2
First the Catenoid:
x1=(1/g^2-1)/2
y1=*((1/g^2+1)/2
z1=1/g
second the Helicoid:
x2=-(1/g^2+1)/2
y2=-I(1/g^2-1)/2
z2=-I/g
These form the planes (plane waves)
x=x1+y1+z1
y=x2+y2+z2
r=Sqrt[x^2+y^2)
w=Atan(x,y)
(f3,g3)=(Log(r),w)
There are
6!/(3!*3!)=20
Combinations to give distinct planes.
The combinations of planes are
20!/(18!*2!)=190
The Hopf type of equation is:
(x1^2+y1^2+z1^2+x2^2+y2^2+z2^2)^3=x3^2+y3^2+z3^2=0
/It seems strange ( cheating?) , but the proof it that zero equals zero
in all cases.
All 190 of them. So if the helicoids are electromagnetic
and the catenoids are gravitational, there are 190
resulting three space fields for the interaction of photons with
gravitons.
Hubert Gollek wrote:

> I had a look at your formulas, turned it into a Mathematica notebook
> and studied
> its invariants, transformed the complex parametrization, trying to
> find out whether it is
> a some other known surface in a nonstandard parametrization.
> At first I had to impose some corections in the Weierstrass -
> representation
> (two signs and a factor 2 in the 3-rd component).
> Finally I got a nice picture that looks similar to other known ones.
> Probably some other parametrization of the catenoid?
>
> best regards
>
> Hubert Gollek
>
> Roger Bagula schrieb:
>
>> --
>> Respectfully, Roger L. Bagula
>> tftn@..., 11759Waterhill Road, Lakeside,Ca 92040-2905,tel:
>>
>> 619-5610814 :
>> URL : http://home.earthlink.net/~tftn
>> URL : http://victorian.fortunecity.com/carmelita/435/
>>
>>
>
Respectfully, Roger L. Bagula
tftn@..., 11759Waterhill Road, Lakeside,Ca 92040-2905,tel:
619-5610814 :