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Re: [2IIM CAT Prep] Ratio, proportions

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  • Monisha Raj
    lets anup s last yr salary be 2x and bunty s last yr salary be 3x......let this yr salary of anup and bunty be a and b respectively........now (2x)/a=3/4
    Message 1 of 13 , Aug 3, 2011
      lets anup's last yr salary be 2x and bunty's last yr salary be 3x......
      let this yr salary of anup and bunty be a and b respectively........
      now (2x)/a=3/4 ->(1)
              (3x/b)=5/7 ->(2)
      then a=8x/3
             b=21x/5
        difference in dis yr salary ie a-b=1150
      (8x/3) - (21x/5)=1150

      solving we get x=750
         then bunty's dis yr salary  is 21x/5  = 3150
    • mohit gupta
      data sufficiency If N is a natural number then number of factors of N^2 is ... A. N has 12 factors. B. N^3 has 70 factors. pls ans with xplanation
      Message 2 of 13 , Aug 16, 2011
        data sufficiency
        If N is a natural number then number of factors of N^2 is ...

        A. N has 12 factors.
        B. N^3 has 70 factors.



        pls ans with xplanation
      • Rajesh Balasubramanian
        N has 12 factors = N can be of the form p^11 or p*q^5 or p^2 * q^3. So, this is not sufficient N^3 has 70 factors 70 can be written as 70 * 1 = N^3 = p^69
        Message 3 of 13 , Aug 16, 2011
          N has 12 factors => N can be of the form p^11 or p*q^5 or p^2 * q^3. So, this is not sufficient
          N^3 has 70 factors
           
          70 can be written as
          70 * 1 => N^3 = p^69 possible => N = p^ 23
          35 * 2 => N^3 =  p^34 * q  Not possible as this cannot be a perfect cube
          5 * 14 => N^3 =  p^4 * q^13 Not possible as this cannot be a perfect cube
          7 * 10 => N^3 = p^6 * q ^ 9 Possible => N = P^2 * q^3
           
          So, this alone is not sufficient.
           
          Both combined together, we can say N has to be of the form p^2 * q^3 and therefore number of factors of N^2 can be found.
           
          Good question, but to be honest I do not think CAT will ask a question even as tough as this.
           
          Cheers,
          Rajesh
          2IIM


           
          On Wed, Aug 17, 2011 at 4:38 AM, mohit gupta <mohit_luvkush@...> wrote:
           

          data sufficiency
          If N is a natural number then number of factors of N^2 is ...

          A. N has 12 factors.
          B. N^3 has 70 factors.



          pls ans with xplanation


        • mohit gupta
          dere r 6 letters and 6 addressed envelops... what is the proabability that exactly 3 are in wrong envelops..
          Message 4 of 13 , Aug 18, 2011
            dere r 6 letters and 6 addressed envelops...


            what is the proabability that exactly 3 are in wrong envelops..


          • Yuv Bansal
            I think it should be 2400.. because you take 3 letters at random which is 6C3 then you multiply by the number of ways each will go in so 6*5*4 6C3*6*5*4 = 2400
            Message 5 of 13 , Aug 19, 2011
              I think it should be 2400..
              because you take 3 letters at random which is 6C3 then you multiply by the number of ways each will go in so 6*5*4
              6C3*6*5*4 = 2400


              From: mohit gupta <mohit_luvkush@...>
              To: "ascent4cat@yahoogroups.com" <ascent4cat@yahoogroups.com>
              Sent: Friday, August 19, 2011 1:11 AM
              Subject: Re: [2IIM CAT Prep] Ratio, proportions

               
              dere r 6 letters and 6 addressed envelops...


              what is the proabability that exactly 3 are in wrong envelops..




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