- lets anup's last yr salary be 2x and bunty's last yr salary be 3x......let this yr salary of anup and bunty be a and b respectively........now (2x)/a=3/4 ->(1)(3x/b)=5/7 ->(2)then a=8x/3b=21x/5difference in dis yr salary ie a-b=1150(8x/3) - (21x/5)=1150solving we get x=750then bunty's dis yr salary is 21x/5 = 3150
- data sufficiencyIf N is a natural number then number of factors of N^2 is ...

A. N has 12 factors.

B. N^3 has 70 factors.pls ans with xplanation - N has 12 factors => N can be of the form p^11 or p*q^5 or p^2 * q^3. So, this is not sufficientN^3 has 70 factors70 can be written as70 * 1 => N^3 = p^69 possible => N = p^ 2335 * 2 => N^3 = p^34 * q Not possible as this cannot be a perfect cube5 * 14 => N^3 = p^4 * q^13 Not possible as this cannot be a perfect cube7 * 10 => N^3 = p^6 * q ^ 9 Possible => N = P^2 * q^3So, this alone is not sufficient.Both combined together, we can say N has to be of the form p^2 * q^3 and therefore number of factors of N^2 can be found.Good question, but to be honest I do not think CAT will ask a question even as tough as this.Cheers,Rajesh2IIM

On Wed, Aug 17, 2011 at 4:38 AM, mohit gupta <mohit_luvkush@...> wrote:data sufficiencyIf N is a natural number then number of factors of N^2 is ...

A. N has 12 factors.

B. N^3 has 70 factors.

pls ans with xplanation - I think it should be 2400..because you take 3 letters at random which is 6C3 then you multiply by the number of ways each will go in so 6*5*46C3*6*5*4 = 2400
**From:**mohit gupta <mohit_luvkush@...>**To:**"ascent4cat@yahoogroups.com" <ascent4cat@yahoogroups.com>**Sent:**Friday, August 19, 2011 1:11 AM**Subject:**Re: [2IIM CAT Prep] Ratio, proportionsdere r 6 letters and 6 addressed envelops...what is the proabability that exactly 3 are in wrong envelops..