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## Re: [2IIM CAT Prep] CAT Number Theory - Questions on Remainders

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• 1. 7^45 = 7(7^44) = 7(2401)^11 = 7(01)^11 = 7(01) = 07. 2. 3^90 + 5^90 = 9^45 + 25^45 is always divisible by (9 + 25) = 34. So remainder is zero. 3. 4 values -
Message 1 of 4 , Nov 10, 2010
1. 7^45 = 7(7^44) = 7(2401)^11 = 7(01)^11 = 7(01) = 07.
2. 3^90 + 5^90 = 9^45 + 25^45 is always divisible by (9 + 25) = 34. So remainder is zero.
3. 4 values - 1, 5, 7, 11.

From: Rajesh Balasubramanian <rajesh@...>
To: ascent4cat@yahoogroups.com
Sent: Mon, November 8, 2010 10:57:25 PM
Subject: [2IIM CAT Prep] CAT Number Theory - Questions on Remainders

Hi all,

Here are a few more questions on Number Theory based on remainders. They have also been posted at ou blog - http://iimcat.blogspot.com/2010/11/questions-on-number-theory-remainder.html.

1. What are the last two digits of the number 7 45 ?

2. What is the remainder when we divide 390 + 590 by 34?

3. N2 leaves a remainder of 1 when divided by 24. What are the possible remainders we can get if we divide N by 12?

Cheers all,
Rajesh
99626 48484
New CAT2011 batches starting @ Chennai
Nov 13th @ Velachery, Nov 20th @ Mylapore

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