## Re: [2IIM CAT Prep] Re: CAT Question - x=2sinx, if x>0

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• Message 1 of 4 , Jun 29, 2010
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On Fri, 25 Jun 2010 10:55 IST Revathi wrote:

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>@jayasree

>it is mentioned in the Question that x >0 .
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>--- On Sat, 19/6/10, jayashree <coolsweettwins@...> wrote:
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>From: jayashree <coolsweettwins@...>
>Subject: [2IIM CAT Prep] Re: CAT Question - x=2sinx, if x>0
>To: ascent4cat@yahoogroups.com
>Date: Saturday, 19 June, 2010, 8:46 PM
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>i think the answer is one solution because only for zero the sine value is zero(i.e zero/2) for larger nos. the eqn will not satisfy since sine varies between 1 and 0
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>correct me if i am wrong
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>regards,
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>--- In ascent4cat@yahoogroups.com, "G.Senthil Kumar" <senthilashok@...> wrote:
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>> HI,
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>>  Need your help to solve this question.
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>> For x = 2 sin x, x > 0, the number of solutions for x is:
>> (a) None (b) One (c) Two (d) Three (e) Four
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>> thanks
>> Senthil
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