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Re: [2IIM CAT Prep] Re: CAT Question - x=2sinx, if x>0

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  • subhasis dhara
    Message 1 of 4 , Jun 29, 2010
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      On Fri, 25 Jun 2010 10:55 IST Revathi wrote:

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      >@jayasree

      >it is mentioned in the Question that x >0 .
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      >--- On Sat, 19/6/10, jayashree <coolsweettwins@...> wrote:
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      >From: jayashree <coolsweettwins@...>
      >Subject: [2IIM CAT Prep] Re: CAT Question - x=2sinx, if x>0
      >To: ascent4cat@yahoogroups.com
      >Date: Saturday, 19 June, 2010, 8:46 PM
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      >

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      >i think the answer is one solution because only for zero the sine value is zero(i.e zero/2) for larger nos. the eqn will not satisfy since sine varies between 1 and 0
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      >correct me if i am wrong
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      >regards,
      >madhu
      >
      >--- In ascent4cat@yahoogroups.com, "G.Senthil Kumar" <senthilashok@...> wrote:
      >>
      >> HI,
      >>  
      >>  Need your help to solve this question.
      >>  
      >> For x = 2 sin x, x > 0, the number of solutions for x is:
      >> (a) None (b) One (c) Two (d) Three (e) Four
      >>  
      >> thanks
      >> Senthil
      >>
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