## Re: Numbers

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• ... (2)87 is the smallest no. which when divided by 13 leaves 9 and when divided by 17 leaves 2 as the remainder.
Message 1 of 10 , Jun 15, 2009
--- In ascent4cat@yahoogroups.com, Maha lakshmi <maha.b.lakshmi@...> wrote:
>
> Hi Friends,
>
> Can any one help in sloving the following problems
>
> 1) Find the Number of ways in which 24700 can be expressed as a product of
> two co-primes?
> 2) Find the smalles number which when divided by 13 leaves 9 as the
> remainder and when divided by 17 leaves 2 as the remainder?
>
> Thanks & Regards,
>
> --
>
> Mahalakshmi.B
>ans-(1)there will be 8 ways in which 24700 can be expressed as a product of two co-prime.
(2)87 is the smallest no. which when divided by 13 leaves 9 and when divided by 17 leaves 2 as the remainder.
• answer for first ques in 19 24700=2^2 * 5^2 * 13 * 19.. ... From: Maha lakshmi Subject: [2IIM CAT Prep] Numbers To:
Message 2 of 10 , Jul 9, 2009
 answer for first ques in 19 24700=2^2 * 5^2 * 13 * 19.. --- On Tue, 5/5/09, Maha lakshmi wrote:From: Maha lakshmi Subject: [2IIM CAT Prep] NumbersTo: ascent4cat@yahoogroups.comDate: Tuesday, 5 May, 2009, 8:15 AMHi Friends, Can any one help in sloving the following problems 1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder? Thanks & Regards,-- Mahalakshmi. B

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• hi, answer for 1 question is 8 Number of ways a number can be expressed as a product of two co-primes is 2^(n-1) (^ - power, n - different prime factors of
Message 3 of 10 , Jul 17, 2009
hi,
answer for 1 question is 8
Number of ways a number can be expressed as a product of two co-primes is 2^(n-1) (^ - power, n - different prime factors of d number).
here 24700=13*19*5*5*2*2
n=4
so 2^3 = 8

--- In ascent4cat@yahoogroups.com, vimlesh patelia <vimlesh_21mech@...> wrote:
>
> Hi Maha Lakshmi,
>
>
>
> Regards,
> Vimlesh
>
>
>
>
> ________________________________
> From: Maha lakshmi <maha.b.lakshmi@...>
> To: ascent4cat@yahoogroups.com
> Sent: Tuesday, 5 May, 2009 1:45:52 PM
> Subject: [2IIM CAT Prep] Numbers
>
>
>
>
>
> Hi Friends,
>
> Can any one help in sloving the following problems
>
> 1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?
> 2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder?
>
> Thanks & Regards,
> --
>
> Mahalakshmi. B
>
>
>
>
>
> Own a website.Get an unlimited package.Pay next to nothing.*Go to http://in.business.yahoo.com/
>
• hi maha lakshmi as vimlesh said answer 87 is right method to get is... Number ca be written as 13d1+9 = 17d2+2 or 13d1+7 = 17*d2..... so we have to find a
Message 4 of 10 , Jul 21, 2009
hi maha lakshmi

as vimlesh said answer 87 is right method to get is...

Number ca be written as  13d1+9 = 17d2+2

or 13d1+7 = 17*d2.....
so we have to find a smallest value of d1 such that 13d1+7 ..is copletly divisible by 17...
we get this value for d1=6...that is 13*6+7==85
but this 85 == 13d1+7..and our number was 13d1+9...so the required smallest no. is 87....

On Mon, Jun 15, 2009 at 12:56 PM, vimlesh patelia wrote:

Hi Maha Lakshmi,

Regards,
Vimlesh

From: Maha lakshmi <maha.b.lakshmi@...>
To: ascent4cat@yahoogroups.com
Sent: Tuesday, 5 May, 2009 1:45:52 PM
Subject: [2IIM CAT Prep] Numbers

Hi Friends,

Can any one help in sloving the following problems

1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?
2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder?

Thanks & Regards,

--

Mahalakshmi. B

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Prakash Awasthy
• sandeep 1 * 24700 is also a case,, so it will get total to 11 cases ... From: kirik pinky Subject: Re: [2IIM CAT Prep] Numbers To:
Message 5 of 10 , Jul 31, 2009
sandeep 1 * 24700 is also a case,,
so it will get total to 11 cases

--- On Mon, 15/6/09, kirik pinky <kiriknpinky@...> wrote:

From: kirik pinky <kiriknpinky@...>
Subject: Re: [2IIM CAT Prep] Numbers
To: ascent4cat@yahoogroups.com
Date: Monday, 15 June, 2009, 1:48 PM

 Hi, 1) 24700 = 247*100 = 13 x 19 x 2^2 x 5^2 (expressed in prime numbers) Number of ways of obtaining m x n such that they are coprime and also mx n = 24700 is4C1+ 4C2 = 4 + 6 = 10. Hopefully this is right.Sandeep IIT MADRAS--- On Tue, 5/5/09, Maha lakshmi wrote:From: Maha lakshmi Subject: [2IIM CAT Prep] NumbersTo: ascent4cat@yahoogro ups.comDate: Tuesday, 5 May, 2009, 1:45 PMHi Friends, Can any one help in sloving the following problems 1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder? Thanks & Regards,-- Mahalakshmi.. B

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• Wikipedia In mathematics, the integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently,
Message 6 of 10 , Aug 10, 2009

Wikipedia

In mathematics, the integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1.[1] The notation a    b is sometimes used to indicate that a and b are relatively prime.[2

For example, 6 and 35 are coprime, but 6 and 27 are not coprime because they are both divisible by 3. The number 1 is coprime to every inte

so 1*24700 should not be a case .

PRASHANT JAIN

From: Muskan Soni <soni.muskan@...>
To: ascent4cat@yahoogroups.com
Sent: Friday, 31 July, 2009 1:43:46 PM
Subject: Re: [2IIM CAT Prep] Numbers

sandeep 1 * 24700 is also a case,,
so it will get total to 11 cases

--- On Mon, 15/6/09, kirik pinky <kiriknpinky@ yahoo.co. in> wrote:

From: kirik pinky <kiriknpinky@ yahoo.co. in>
Subject: Re: [2IIM CAT Prep] Numbers
To: ascent4cat@yahoogro ups.com
Date: Monday, 15 June, 2009, 1:48 PM

 Hi, 1) 24700 = 247*100 = 13 x 19 x 2^2 x 5^2 (expressed in prime numbers) Number of ways of obtaining m x n such that they are coprime and also mx n = 24700 is4C1+ 4C2 = 4 + 6 = 10. Hopefully this is right.Sandeep IIT MADRAS--- On Tue, 5/5/09, Maha lakshmi wrote:From: Maha lakshmi Subject: [2IIM CAT Prep] NumbersTo: ascent4cat@yahoogro ups.comDate: Tuesday, 5 May, 2009, 1:45 PMHi Friends, Can any one help in sloving the following problems 1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder? Thanks & Regards,-- Mahalakshmi. . B

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• 1)_     HERE, V NEED TO FIND OUT 2 CO PRIME NOS THAT HAS PROUCT AS 24700. THESE R THE POSSIBILITIES: 13*4  &  19*25 13*25 &  19*4 ANY OTHE COMBINATION U
Message 7 of 10 , Aug 11, 2009
1)_

HERE, V NEED TO FIND OUT 2 CO PRIME NOS THAT HAS PROUCT AS 24700.

THESE R THE POSSIBILITIES:

13*4  &  19*25

13*25 &  19*4

ANY OTHE COMBINATION U WIL TAKE WILL HAVE H.C.F. IN COMMON SO, MY ANSWER IS 2… PLZ, CONFIRM THIS ONE…

2)_

HERE, WE GET 2 EQ:

13X+9 & 17X+2 NOW THE NO. WUD BE MULTIPLE OF BOTH THIS EQ.

SO YHE NO WUD BE 87 THAT SATISFIES BOTH THE EQ.

From: kirik pinky <kiriknpinky@...>
To: ascent4cat@yahoogroups.com
Sent: Monday, June 15, 2009 6:48:38 AM
Subject: Re: [2IIM CAT Prep] Numbers

 Hi, 1) 24700 = 247*100 = 13 x 19 x 2^2 x 5^2 (expressed in prime numbers) Number of ways of obtaining m x n such that they are coprime and also mx n = 24700 is4C1+ 4C2 = 4 + 6 = 10. Hopefully this is right.Sandeep IIT MADRAS --- On Tue, 5/5/09, Maha lakshmi wrote:From: Maha lakshmi Subject: [2IIM CAT Prep] NumbersTo: ascent4cat@yahoogro ups.comDate: Tuesday, 5 May, 2009, 1:45 PMHi Friends, Can any one help in sloving the following problems 1) Find the Number of ways in which 24700 can be expressed as a product of two co-primes?2) Find the smalles number which when divided by 13 leaves 9 as the remainder and when divided by 17 leaves 2 as the remainder? Thanks & Regards,-- Mahalakshmi. B