- hi guys....i think this is the right answer[tan(63)+tan(27)] - [tan(81)+tan(9)]= [sin90/(cos63*cos27)]-[sin90/(cos81*cos9)]

=4.503..... check with your formulas....--- On

**Tue, 2/12/08, vimlesh patelia**wrote:*<vimlesh_21mech@...>*From: vimlesh patelia <vimlesh_21mech@...>

Subject: Re: [2IIM CAT Prep] question trignometry

To: ascent4cat@yahoogroups.com

Date: Tuesday, 2 December, 2008, 3:09 PMHi all,I don't think the sum of tanØ and tanß would be indeterminate.If you do it by calcu then also you may come to know.*Regards,**Vimlesh Patelia.*P

*please consider the environment before printing this e-mail.*

**From:**Haneef Mohammad <haneef0786@gmail. com>**To:**ascent4cat@yahoogro ups.com**Sent:**Monday, 1 December, 2008 5:14:46 PM**Subject:**Re: [2IIM CAT Prep] question trignometryApply tanA + tan B = tan (A+B) (1-tanA.tanB)

tan9 + tan81 - (tan27 + tan63)

tan90.(1 - tan9.tan81) - tan90.(1 - tan27.tan63)

Infinity - Infinity

Indeterminate.

~Cheers,

Haneef.On Sat, Nov 29, 2008 at 6:53 PM, bharadwaja y <bharadwajasharma_ y@...> wrote:hi clarify my doubt,tan9-tan27-tan63+ tan81=need srt cut

Check out the all-new face of Yahoo! India. Click here.

Add more friends to your messenger and enjoy! Invite them now. - well the correct solution is here ( i am writing down this solution

becuz michael arun`s equations and ans are different his equations

give negative ans but the ans is positive and also to remove sum

confusion abt formulas of trignometry)

TAN9 -TAN27 -TAN63 +TAN81

USE THE FORMULA

TAN(A)+TAN(B)=SIN(A+B)/COS(A)COS(B)

the domain for this formula is A nÎ and B Î

so use this on 9 and 81 & the other group wud be 27 and 63

NOTE:- we cannt use the formula

TAN(A+B)=TANA-TANB/1+TANA*TANB

cuz the domain for this formula is AnÎ+Î/2 BmÎ+Î/2

and A+BkÎ+Î/2

so the question of infinity doesnt arise cuz u cant use this formula

on the group (9,81) and (27,63) cuz the sum is =Î/2

more over - isnt infinity , its indeterminate and theres a

difference between indeterminate quatity and infinity

+ means that its lager than all the real numbes however large it may

be , we dont know its value so how can u find its difference thats y

the difference cant be found hence its called inderterminate and that

is not equal to infinity

so using the formula

TAN(A)+TAN(B)=SIN(A+B)/COS(A)COS(B)

sin90/cos9cos81 - sin90/cos27cos63

now multiply numerator and denominator by 2

2/2cos9cos81 - 2/2cos27cos63

now use the formula 2cosAcosB=cos(A+B)+cos(A-B)

and also remember that cos(-Æ)=cosÆ

so it boils down to

2/cos72 - 2/cos36

i hope u guys know that cos36=(1/4)(ã5+ 1 )

cos72=2cos^2(32)-1

so now put the values

my ans came to be abt 4.002

tc all

and happy new year

RAHUL SAINI

>

> On Sat, Nov 29, 2008 at 6:53 PM, bharadwaja y

> <bharadwajasharma_y@...>wrote:

>

> > hi clarify my doubt,

> >

> > tan9-tan27-tan63+tan81=

> >

> > need srt cut

> >

> >

> >

>

>

>

> On Sat, Nov 29, 2008 at 6:53 PM, bharadwaja y

> <bharadwajasharma_y@...>wrote:

>

> > hi clarify my doubt,

> >

> > tan9-tan27-tan63+tan81=

> >

> > need srt cut

> >

> >

> >

> - well the correct solution is here ( i am writing down this solution

becuz michael arun`s equations and ans are different his equations

give negative ans but the ans is positive and also to remove sum

confusion abt formulas of trignometry)

TAN9 -TAN27 -TAN63 +TAN81

USE THE FORMULA

TAN(A)+TAN(B)=SIN(A+B)/COS(A)COS(B)

the domain for this formula is A ≠ nπ and B ≠ π

so use this on 9 and 81 & the other group wud be 27 and 63

NOTE:- we cannt use the formula

TAN(A+B)=TANA-TANB/1+TANA*TANB

cuz the domain for this formula is A≠nπ+π/2 B≠mπ+π/2

and A+B≠kπ+π/2

so the question of infinity doesnt arise cuz u cant use this formula

on the group (9,81) and (27,63) cuz the sum is =π/2

more over ∞-∞ isnt infinity , its indeterminate and theres a

difference between indeterminate quatity and infinity

+∞ means that its lager than all the real numbes however large it may

be , we dont know its value so how can u find its difference thats y

the difference cant be found hence its called inderterminate and that

is not equal to infinity

so using the formula

TAN(A)+TAN(B)=SIN(A+B)/COS(A)COS(B)

sin90/cos9cos81 - sin90/cos27cos63

now multiply numerator and denominator by 2

2/2cos9cos81 - 2/2cos27cos63

now use the formula 2cosAcosB=cos(A+B)+cos(A-B)

and also remember that cos(-θ)=cosθ

so it boils down to

2/cos72 - 2/cos36

i hope u guys know that cos36=(1/4)(√5+ 1 )

cos72=2cos^2(32)-1

so now put the values

my ans came to be abt 4.002

tc all

and happy new year

RAHUL SAINI

>

> On Sat, Nov 29, 2008 at 6:53 PM, bharadwaja y

> <bharadwajasharma_y@...>wrote:

>

> > hi clarify my doubt,

> >

> > tan9-tan27-tan63+tan81=

> >

> > need srt cut

> >

--- In ascent4cat@yahoogroups.com, michael arun <mma_gct@...> wrote:

>

> hi guys....

> Â Â Â Â Â Â Â Â Â Â Â Â i think this is the right answer

> Â

> [tan(63)+tan(27)] - [tan(81)+tan(9)]

> Â

> = [sin90/(cos63*cos27)]-[sin90/(cos81*cos9)]

>

> =4.503..... check with your formulas....

> Â

> Â

>

> --- On Tue, 2/12/08, vimlesh patelia <vimlesh_21mech@...> wrote:

>

> From: vimlesh patelia <vimlesh_21mech@...>

> Subject: Re: [2IIM CAT Prep] question trignometry

> To: ascent4cat@yahoogroups.com

> Date: Tuesday, 2 December, 2008, 3:09 PM

>

>

>

>

>

>

>

>

>

> Hi all,

> I don't think the sum ofÂ tanÃ and tanÃÂ would be indeterminate.

> If youÂ do it by calcu then also youÂ mayÂ come to know.

> Â

> Regards,

> Vimlesh Patelia.

>

> P Â please consider the environment before printingÂ this e-mail.

>

>

>

>

>

>

> From: Haneef Mohammad <haneef0786@gmail. com>

> To: ascent4cat@yahoogro ups.com

> Sent: Monday, 1 December, 2008 5:14:46 PM

> Subject: Re: [2IIM CAT Prep] question trignometry

>

>

>

> Apply tanA + tan B = tan (A+B) (1-tanA.tanB)

>

> tan9 + tan81 - (tan27 + tan63)

>

> tan90.(1 - tan9.tan81) - tan90.(1 - tan27.tan63)

>

> Infinity - Infinity

>

> Indeterminate.

>

> ~Cheers,

> Haneef.

>

>

>

> On Sat, Nov 29, 2008 at 6:53 PM, bharadwaja y <bharadwajasharma_

y@...> wrote:

>

>

>

>

>

>

>

>

>

>

>

> hi clarify my doubt,

> tan9-tan27-tan63+ tan81=

> need srt cut

>

>

>

>

> Check out the all-new face of Yahoo! India. Click here.

>

>

>

>

>

>

>

>

>

>

>

>

>

>

> Add more friends to your messenger and enjoy! Go to

http://messenger.yahoo.com/invite/

> tan90 is not equal to zero, its infinity.

Sandeep

IIT MADRAS--- On

**Mon, 1/12/08, amit jain**wrote:*<amitjain3325@...>*

From: amit jain <amitjain3325@...>

Subject: Re: [2IIM CAT Prep] question trignometry

To: ascent4cat@yahoogroups.com

Date: Monday, 1 December, 2008, 6:59 PMcheck formula of tan a + tan b as here 63+27= 90 & 81+7 = 90. the trick lies their. i think answer will be zero bcoz of that very reason pl. confirm the same.RegardsAmit

--- On**Sat, 11/29/08, bharadwaja y**wrote:*<bharadwajasharma_ y@...>*From: bharadwaja y <bharadwajasharma_ y@...>

Subject: [2IIM CAT Prep] question trignometry

To: "ascent cat" <ascent4cat@yahoogro ups.com>

Date: Saturday, November 29, 2008, 6:53 PMhi clarify my doubt,tan9-tan27-tan63+ tan81=need srt cut

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