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Re: [2IIM CAT Prep] One doubt in Quants

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  • raj kumar
    HI this is a CAT 2006 Question The way to take the problem Let us take the L.C.M of (2,3,4,6,12) (2^1/2)^12, (3^1/3)^12 , (4^1/4)^12 ,(6^1/6)^12, (12^1/12)^12
    Message 1 of 8 , Nov 26, 2008
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      HI this is a CAT 2006 Question
       
      The way to take the problem
      Let us take the L.C.M of (2,3,4,6,12)
       
      (2^1/2)^12, (3^1/3)^12 , (4^1/4)^12 ,(6^1/6)^12, (12^1/12)^12
       
      we get
      2^6 , 3^4 , 4^3 ,6^2 , 12^1
       
      so from above solution we can conclude 3^1/3  is the largest.
       
      Regards
      D.Rajkumar

       sharan kurkoti <sharankurkoti@...> wrote:
      Hi Murali,

      whatever lohit has given explaination is correct.

      please do read the mail once again...

      and your concept i really dis agree with it... all are not equal.

      On Sat, Nov 22, 2008 at 3:21 PM, murlidhar gone <gmurli_uict@ yahoo.co. in> wrote:
      All are equal..
       
      any number raised to 1 is the number itself. In that way for given examples i.e 2^1 = 2 hence 2/2=1, likewise for all others i.e. 3^1/3=3/3=1, 6^1/6=6/6=1, 12^1/12=12/12= 1. hence each term is equal to 1.

       


      From: karthik srinivas <karthik187@yahoo. com>
      To: ascent4cat@yahoogro ups.com
      Sent: Thursday, 13 November, 2008 6:14:53 PM
      Subject: [2IIM CAT Prep] One doubt in Quants

      Hi Team,

                 Kindly clarify me in this question.

      Which of the following is the largest.

      2^1/2,3^1/3, 6^1/6,12^ 1/12 with explanation ASAP please.

      Regards,
      Karthik S



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      Regards
      ~Sharan Kurkoti
      "Tell me and I'll forget; show me and I may remember; involve me and I'll understand"


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    • kirik pinky
      Answer can be memorized if you remember the graph of n^1/n. There is only one maximum which occurs at n = e (approx 2.718) So value n closest to this will have
      Message 2 of 8 , Jun 16, 2009
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        Answer can be memorized if you remember the graph of n^1/n. There is only one maximum which occurs at n = e (approx 2.718) So value n closest to this will have greater value of n^(1/n). So n = 3 is the answer.

        Sandeep
        IIT MADRAS


        --- On Thu, 27/11/08, raj kumar <dv_rajkumar@...> wrote:

        From: raj kumar <dv_rajkumar@...>
        Subject: Re: [2IIM CAT Prep] One doubt in Quants
        To: ascent4cat@yahoogroups.com
        Date: Thursday, 27 November, 2008, 9:54 AM

        HI this is a CAT 2006 Question
         
        The way to take the problem
        Let us take the L.C.M of (2,3,4,6,12)
         
        (2^1/2)^12, (3^1/3)^12 , (4^1/4)^12 ,(6^1/6)^12, (12^1/12)^12
         
        we get
        2^6 , 3^4 , 4^3 ,6^2 , 12^1
         
        so from above solution we can conclude 3^1/3  is the largest.
         
        Regards
        D.Rajkumar

         sharan kurkoti <sharankurkoti@ gmail.com> wrote:
        Hi Murali,

        whatever lohit has given explaination is correct.

        please do read the mail once again...

        and your concept i really dis agree with it... all are not equal.

        On Sat, Nov 22, 2008 at 3:21 PM, murlidhar gone <gmurli_uict@ yahoo.co. in> wrote:
        All are equal..
         
        any number raised to 1 is the number itself. In that way for given examples i.e 2^1 = 2 hence 2/2=1, likewise for all others i.e. 3^1/3=3/3=1, 6^1/6=6/6=1, 12^1/12=12/12= 1. hence each term is equal to 1.

         


        From: karthik srinivas <karthik187@yahoo. com>
        To: ascent4cat@yahoogro ups.com
        Sent: Thursday, 13 November, 2008 6:14:53 PM
        Subject: [2IIM CAT Prep] One doubt in Quants

        Hi Team,

                   Kindly clarify me in this question.

        Which of the following is the largest.

        2^1/2,3^1/3, 6^1/6,12^ 1/12 with explanation ASAP please.

        Regards,
        Karthik S



        Connect with friends all over the world. Get Yahoo! India Messenger.



        --
        Regards
        ~Sharan Kurkoti
        "Tell me and I'll forget; show me and I may remember; involve me and I'll understand"


        Add more friends to your messenger and enjoy! Invite them now.


        Explore and discover exciting holidays and getaways with Yahoo! India Travel Click here!
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