- View SourceHi!

We can solve this type of problem using the trick as

below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)

=49-(128/7^5) >1

i.e. 5^7 > 7^5

All d best

Sunil

__________________________________________________________

Yahoo! India Answers: Share what you know. Learn something new

http://in.answers.yahoo.com/ - View SourceSunil Could you elaborate as to how you simplifiedthe following -(7-2)^7/7^5 as 7^2-(2^7/7^5)GSPK

On 10/9/06,**sunil suhana**<luv_sunil10@...> wrote:Hi!

We can solve this type of problem using the trick as

below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)

=49-(128/7^5) >1

i.e. 5^7 > 7^5

All d best

Sunil

__________________________________________________________

Yahoo! India Answers: Share what you know. Learn something new

http://in.answers.yahoo.com/

- View Sourcethe sum of two numbers=144their HCF=24that means one no:=24xother no:=24ynow, 24x+24y=144;by trial error method taking two unlike values of 'x' and 'y'x-=1,y=5: 24(1)+24(5)=144.when you take smaller values of 'x', take bigger values of 'y' and vice-versa.

ANSWER: the nos: are 24 and 120.On 9/15/06,**saurabh maggo**<saurabh_14nov@...> wrote:1. which is larger, 7 to the power 5 or 5 to the power?is there a technique to solve such kind of ques!2. the sum of two nos. is 144. their hcf is 24.find the nos.

Stay in the know. Pulse on the new Yahoo.com. Check it out.

--

Ruli Roy

Email-ruli.roy@...