## Re: [Ascent CAT] problems on numbers

Expand Messages
• Hi! We can solve this type of problem using the trick as below:- (5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5) =49-(128/7^5) 1 i.e. 5^7 7^5 All d best Sunil
Message 1 of 4 , Oct 9, 2006
• 0 Attachment
Hi!
We can solve this type of problem using the trick as
below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)
=49-(128/7^5) >1
i.e. 5^7 > 7^5

All d best
Sunil

__________________________________________________________
Yahoo! India Answers: Share what you know. Learn something new
• Sunil Could you elaborate as to how you simplifiedthe following - (7-2)^7/7^5 as 7^2-(2^7/7^5) GSPK
Message 2 of 4 , Oct 29, 2006
• 0 Attachment
Sunil Could you elaborate as to how you simplifiedthe following -
(7-2)^7/7^5 as 7^2-(2^7/7^5)
GSPK

On 10/9/06, sunil suhana <luv_sunil10@...> wrote:

Hi!
We can solve this type of problem using the trick as
below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)
=49-(128/7^5) >1
i.e. 5^7 > 7^5

All d best
Sunil

__________________________________________________________
Yahoo! India Answers: Share what you know. Learn something new

• the sum of two numbers=144 their HCF=24 that means one no:=24x other no:=24y now, 24x+24y=144; by trial error method taking two unlike values of x and y
Message 3 of 4 , Oct 29, 2006
• 0 Attachment
the sum of two numbers=144
their HCF=24

that means one no:=24x
other no:=24y

now, 24x+24y=144;

by trial error method taking two unlike values of 'x' and 'y'
x-=1,y=5: 24(1)+24(5)=144.
when you take smaller values of 'x', take bigger values of 'y' and vice-versa.

ANSWER: the nos: are 24 and 120.
On 9/15/06, saurabh maggo <saurabh_14nov@...> wrote:

1. which is larger, 7 to the power 5 or 5 to the power?
is there a technique to solve such kind of ques!

2. the sum of two nos. is 144. their hcf is 24.find the nos.

Stay in the know. Pulse on the new Yahoo.com. Check it out.

--
Ruli Roy

Email-ruli.roy@...
Your message has been successfully submitted and would be delivered to recipients shortly.