- Hi!

We can solve this type of problem using the trick as

below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)

=49-(128/7^5) >1

i.e. 5^7 > 7^5

All d best

Sunil

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http://in.answers.yahoo.com/ - Sunil Could you elaborate as to how you simplifiedthe following -(7-2)^7/7^5 as 7^2-(2^7/7^5)GSPK

On 10/9/06,**sunil suhana**<luv_sunil10@...> wrote:Hi!

We can solve this type of problem using the trick as

below:-

(5^7)/(7^5)= (7-2)^7/7^5= 7^2-(2^7/7^5)

=49-(128/7^5) >1

i.e. 5^7 > 7^5

All d best

Sunil

__________________________________________________________

Yahoo! India Answers: Share what you know. Learn something new

http://in.answers.yahoo.com/

- the sum of two numbers=144their HCF=24that means one no:=24xother no:=24ynow, 24x+24y=144;by trial error method taking two unlike values of 'x' and 'y'x-=1,y=5: 24(1)+24(5)=144.when you take smaller values of 'x', take bigger values of 'y' and vice-versa.

ANSWER: the nos: are 24 and 120.On 9/15/06,**saurabh maggo**<saurabh_14nov@...> wrote:1. which is larger, 7 to the power 5 or 5 to the power?is there a technique to solve such kind of ques!2. the sum of two nos. is 144. their hcf is 24.find the nos.

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