## Re: [Ascent CAT] number system problems

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• hey pallavi, ssup ...lisn, al dese probs r quite simple...u jus have to use sum basic rules. solutions: 1) ans is (b) a perfect square can neva end in 2,3,7
Message 1 of 13 , Jul 16, 2006
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hey pallavi,
ssup' ...lisn, al dese probs r quite simple...u jus have to use sum basic rules.
solutions:

1) ans is (b)
a perfect square can neva end in 2,3,7 and 8

2) i dint get ure Q...as in em not actualy clear bout d Q

3) u can solve dis sum by takin few eg.
square of a no. grater den 1000
say for eg: 1001
find the square of 1001 wid the formula (1000+1)^2
ie 1000000+2000+1= 1002001
test for divisibility for 3 is: sum of the digits of the no. shud b divisible by 3
( for eg: 453 : sum of digits is 12. therefore, the no. is divisible by 3
and to find the remainder, divide the sum by 3
for eg: 454 : sum of digits is 13, the no. is not divisible by 3 n d remaider is 1...( divide 13 by 3)
here, is dis sum : sum of digits os 1002001 is 4 , so the remainder is 1
next, square of 1002 is 1004004 and dis no. is divisible by 3
square of 1003 is 1006009, it is not divisible by 3 and remainder is 1.... so on n so forth..
so the ans is option (a) 1 always

4) u get the upper limit for x+y wen d value for x and y is maximum which is 4 and 3 resp in dis case and the lower limit for x-y is wen d value for x and y is d lowest, which is 2 and 1 resp in dis case.
therefore, x+y/x-y = 4+3/2-1
=7/1
=7
which is ans option (b) 7

5)
pallavi aggarwal <pal_agg2003@...> wrote:
1. which of the following is not a perfect square?
a) 1,00,856                  b) 3,25,137      c) 9,45,729      d) all of these
1. some birds settled on the branches of a tree. Ffirst, they sat one to a branch and there was one bird too many. Next they sat two to a branch and there was one branch too many. How many branches were there?
a) 3      b) 4      c) 5      d) 6
1. the square of a number greater than 1000 that is not divisible by 3, wen divided by 3, leaves a remainder of
a) 1 always       b) 2 always       c) either 1 or 2              d)cant be said
1. if 2<x<4 and 1<y<3, then find the ratio of the upper limit for x+y and the lower limit of x-y
a) 6      b) 7      c) 8      d) none of these

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• Hi there, Pl. solve the following puzzle. Q : My friend has four uncles of different height. Their average height is 74 inches & diference in height amongst
Message 2 of 13 , Jul 16, 2006
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Hi there,
Pl. solve the following puzzle.

Q : My friend has four uncles of different height. Their average height is 74 inches & diference in height amongst the first three uncle is two inches. The difference between the third & the fourth uncle is 6 inches. Find out the height of each uncle.

PS : I am getting the answer as 63,65,67 & 61. But the answer is 70,72,74 & 80. Can anybody solve this for me ????

Mit.

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• ... d) all of these ... souare.hence option b. ... one to a branch and there was one bird too many. Next they sat two to a branch and there was one branch too
Message 3 of 13 , Jul 22, 2006
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--- In ascent4cat@yahoogroups.com, pallavi aggarwal
<pal_agg2003@...> wrote:
>
>
> which of the following is not a perfect square?
>
> a) 1,00,856 b) 3,25,137 c) 9,45,729
d) all of these
> the no having 2,3,7 or 8 in the last can never b a perfect
souare.hence option b.
>
>
> some birds settled on the branches of a tree. Ffirst, they sat
one to a branch and there was one bird too many. Next they sat two
to a branch and there was one branch too many. How many branches
were there?
>
> a) 3 b) 4 c) 5 d) 6
> thi s one gets better solved through hit & trial th correct
option would b a i.e.there r 3 branches 7 4 birdds
>
> the square of a number greater than 1000 that is not divisible
by 3, wen divided by 3, leaves a remainder of
>
> a) 1 always b) 2 always c) either 1 or
2 d)cant be said
>
> souare of a no when divided by 3 always leaves a remainder 1 hance
option a chek it for any no.
>
> if 2<x<4 and 1<y<3, then find the ratio of the upper limit for
x+y and the lower limit of x-y
>
> a) 6 b) 7 c) 8 d) none of these
>
> the correct option wouold b bi.e. 7 because max value of x & y
would b near 4& 3 approx respectively.& min 2& 1 approx .hence 7
>
>
>
> sorry for being late.please confirm if u r satisfied with
>
> ---------------------------------
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>
• Dear Aarti, Commendable solutions.Though, i differ with u in these respects. Q2) Suppose the no. of branches is x, then the no. of birds will b x+1.According
Message 4 of 13 , Aug 2, 2006
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Dear Aarti,

Commendable solutions.Though, i differ with u in these
respects.

Q2) Suppose the no. of branches is x, then the no. of
birds will b x+1.According to the question,
(x+1)/2 + 1=x....solving this it will give, x=3

q3)If u start taking examples like that, u cant say
anything with surity....plus u will waste time.

Any no. which is not divisible by 3 is given as (3m+1)
or (3m+2). where we can choose suitable m according to
the range of values.

Now, Square of such no. = (3m+1)*(3m+1)=9m^2+6m+1. so
remainder will b 1.
Similarly for (3m+2)*(3m+2)

q4) please clarify ur concept in this regard.Suppose
we take x=2 and y=3....then wat is the value of
x-y???Yes, it is -1. So , taking lowest values of x
and y wont give the lowest value of x-y. So, answer
will b none of these.

Punit

--- aarti jain <aartirjain@...> wrote:

> hey pallavi,
> ssup' ...lisn, al dese probs r quite simple...u
> jus have to use sum basic rules.
> solutions:
>
> 1) ans is (b)
> a perfect square can neva end in 2,3,7 and 8
>
> 2) i dint get ure Q...as in em not actualy clear
> bout d Q
>
> 3) u can solve dis sum by takin few eg.
> square of a no. grater den 1000
> say for eg: 1001
> find the square of 1001 wid the formula (1000+1)^2
>
> ie 1000000+2000+1= 1002001
> test for divisibility for 3 is: sum of the digits
> of the no. shud b divisible by 3
> ( for eg: 453 : sum of digits is 12. therefore,
> the no. is divisible by 3
> and to find the remainder, divide the sum by 3
> for eg: 454 : sum of digits is 13, the no. is not
> divisible by 3 n d remaider is 1...( divide 13 by 3)
> here, is dis sum : sum of digits os 1002001 is 4 ,
> so the remainder is 1
> next, square of 1002 is 1004004 and dis no. is
> divisible by 3
> square of 1003 is 1006009, it is not divisible by
> 3 and remainder is 1.... so on n so forth..
> so the ans is option (a) 1 always
>
> 4) u get the upper limit for x+y wen d value for x
> and y is maximum which is 4 and 3 resp in dis case
> and the lower limit for x-y is wen d value for x and
> y is d lowest, which is 2 and 1 resp in dis case.
> therefore, x+y/x-y = 4+3/2-1
> =7/1
> =7
> which is ans option (b) 7
>
> 5)
> pallavi aggarwal <pal_agg2003@...> wrote:
>
> which of the following is not a perfect square?
>
> a) 1,00,856 b) 3,25,137 c)
> 9,45,729 d) all of these
>
>
>
> some birds settled on the branches of a tree.
> Ffirst, they sat one to a branch and there was one
> bird too many. Next they sat two to a branch and
> there was one branch too many. How many branches
> were there?
>
> a) 3 b) 4 c) 5 d) 6
>
>
> the square of a number greater than 1000 that is
> not divisible by 3, wen divided by 3, leaves a
> remainder of
>
> a) 1 always b) 2 always c) either 1 or
> 2 d)cant be said
>
>
>
> if 2<x<4 and 1<y<3, then find the ratio of the
> upper limit for x+y and the lower limit of x-y
>
> a) 6 b) 7 c) 8 d) none of these
>
>
>
>
>
>
> ---------------------------------
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> Catch all the FIFA World Cup 2006 action on Yahoo!
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>
>
>
> ---------------------------------
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• Hi Mitrabhanu Pati, First of all you should realize that, the average of the answer that you are getting i.e. 63, 65, 67, 61 can never be 74 (all no. are
Message 5 of 13 , Aug 2, 2006
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Hi Mitrabhanu Pati,

First of all you should realize that, the average of the answer that you are getting i.e. 63, 65, 67, 61 can never be 74 (all no. are smaller than 74).

Assume the shortest of them to be 'x', then the next one is 'x+2', and after that is 'x+4', and finally 'x+10'. Taking their average to be 74, we get the answer as 70, 72, 74, 80.

Hope it solves your problem. I know you must be thinking that how can we assume them to be standing in the increasing order, so i solved all the possible combinations of it( there were 16 of those) as given below:
x, x+2, x+4, x+10
x,
x+2, x+4, x-2
x, x-2, x-4, x-10
x, x-2, x-4, x+2
x-2, x, x+2, x+8
x-2, x, x+2, x-4
x+2, x, x-2, x-4
x+2, x, x-2, x-8
x+4, x+2, x, x+6
x+4, x+2, x, x-6
x-4, x-2, x, x+6
x-4, x-2, x, x-6
x+10, x+8, x+6, x
x+2, x+4, x+6, x
x-10, x-8, x-6, x
x-2, x-4, x-6, x

Solving all the possible combinations, there were three different answers as:

78, 76, 74, 68
70, 72, 74, 80
73, 75, 77, 71

All three are correct answers, may be the options had just the second one as option. So they marked only this as correct. But your answer can never be correct.

On 7/16/06, Mitrabhanu Pati <mitrabhanu_p@...> wrote:

Hi there,
Pl. solve the following puzzle.

Q : My friend has four uncles of different height. Their average height is 74 inches & diference in height amongst the first three uncle is two inches. The difference between the third & the fourth uncle is 6 inches. Find out the height of each uncle.

PS : I am getting the answer as 63,65,67 & 61. But the answer is 70,72,74 & 80. Can anybody solve this for me ????

Mit.

• HI, For the second question, There are 3 branches and four birds = if one bird per branch then one bird left if two birds per br then one branch left
Message 6 of 13 , Aug 6, 2006
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HI,
For the second question,
There are 3 branches and four birds
=>> if one bird per branch then one bird left
if two birds per br then one branch left
ans:3branches
--- In ascent4cat@yahoogroups.com, aarti jain <aartirjain@...> wrote:
>
> hey pallavi,
> ssup' ...lisn, al dese probs r quite simple...u jus have to use
sum basic rules.
> solutions:
>
> 1) ans is (b)
> a perfect square can neva end in 2,3,7 and 8
>
> 2) i dint get ure Q...as in em not actualy clear bout d Q
>
> 3) u can solve dis sum by takin few eg.
> square of a no. grater den 1000
> say for eg: 1001
> find the square of 1001 wid the formula (1000+1)^2
> ie 1000000+2000+1= 1002001
> test for divisibility for 3 is: sum of the digits of the no.
shud b divisible by 3
> ( for eg: 453 : sum of digits is 12. therefore, the no. is
divisible by 3
> and to find the remainder, divide the sum by 3
> for eg: 454 : sum of digits is 13, the no. is not divisible by 3
n d remaider is 1...( divide 13 by 3)
> here, is dis sum : sum of digits os 1002001 is 4 , so the
remainder is 1
> next, square of 1002 is 1004004 and dis no. is divisible by 3
> square of 1003 is 1006009, it is not divisible by 3 and
remainder is 1.... so on n so forth..
> so the ans is option (a) 1 always
>
> 4) u get the upper limit for x+y wen d value for x and y is
maximum which is 4 and 3 resp in dis case and the lower limit for x-
y is wen d value for x and y is d lowest, which is 2 and 1 resp in
dis case.
> therefore, x+y/x-y = 4+3/2-1
> =7/1
> =7
> which is ans option (b) 7
>
> 5)
> pallavi aggarwal <pal_agg2003@...> wrote:
>
> which of the following is not a perfect square?
>
> a) 1,00,856 b) 3,25,137 c) 9,45,729
d) all of these
>
>
>
> some birds settled on the branches of a tree. Ffirst, they sat
one to a branch and there was one bird too many. Next they sat two
to a branch and there was one branch too many. How many branches
were there?
>
> a) 3 b) 4 c) 5 d) 6
>
>
> the square of a number greater than 1000 that is not divisible
by 3, wen divided by 3, leaves a remainder of
>
> a) 1 always b) 2 always c) either 1 or
2 d)cant be said
>
>
>
> if 2<x<4 and 1<y<3, then find the ratio of the upper limit for
x+y and the lower limit of x-y
>
> a) 6 b) 7 c) 8 d) none of these
>
>
>
>
>
>
> ---------------------------------
> Yahoo! India Answers: Share what you know. Learn something new
> Catch all the FIFA World Cup 2006 action on Yahoo! India Click
here
>
>
>
>
> ---------------------------------
> Talk is cheap. Use Yahoo! Messenger to make PC-to-Phone calls.
Great rates starting at 1¢/min.
>
• ... height is ... two inches. ... Find out ... 70,72,74 ... hey firsst suppose the age of the first to be x than second will be x+2 third will be x+4 and the
Message 7 of 13 , Aug 19, 2006
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>
> > Q : My friend has four uncles of different height. Their average
height is
> > 74 inches & diference in height amongst the first three uncle is
two inches.
> > The difference between the third & the fourth uncle is 6 inches.
Find out
> > the height of each uncle.
> >
> > PS : I am getting the answer as 63,65,67 & 61. But the answer is
70,72,74
> > & 80. Can anybody solve this for me ????
> >
> > Mit.
> >
>
hey firsst suppose the age of the first to be x than second will be
x+2 third will be x+4 and the last will be x+10 now the avg is 74
so x+x+4+x+2+x+10=74*4
4x+16=296
4x=280
x=70
so u can get the age of all ur uncles
• ... U CAN TRY THIS TOO AVG. HIGHT OF 4 UNCLES = 74 inc So total hgt = 74*4 = 296 now let hgt of 1st uncle is x there4 2nd s = x+2, 3rd s = x+4, 4th s= x+10
Message 8 of 13 , Aug 24, 2006
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--- In ascent4cat@yahoogroups.com, "Havi Arora" <haviarora@...> wrote:
> HI ALL

U CAN TRY THIS TOO
AVG. HIGHT OF 4 UNCLES = 74 inc
So total hgt = 74*4 = 296
now let hgt of 1st uncle is "x"
there4 2nd's = x+2, 3rd's = x+4, 4th's= x+10
hence x+(x+2)+(x+4)+(x+10)=296
4x+16 =296
x=70
hence 70, 72, 74, 80
hope i m right.
bye
anjali
> Hi Mitrabhanu Pati,
>
> First of all you should realize that, the average of the answer
that you are
> getting i.e. 63, 65, 67, 61 can never be 74 (all no. are smaller
than 74).
>
> Assume the shortest of them to be 'x', then the next one is 'x+2',
and after
> that is 'x+4', and finally 'x+10'. Taking their average to be 74,
we get the
> answer as 70, 72, 74, 80.
>
> Hope it solves your problem. I know you must be thinking that how
can we
> assume them to be standing in the increasing order, so i solved all
the
> possible combinations of it( there were 16 of those) as given below:
> x, x+2, x+4, x+10
> x, x+2, x+4, x-2
> x, x-2, x-4, x-10
> x, x-2, x-4, x+2
> x-2, x, x+2, x+8
> x-2, x, x+2, x-4
> x+2, x, x-2, x-4
> x+2, x, x-2, x-8
> x+4, x+2, x, x+6
> x+4, x+2, x, x-6
> x-4, x-2, x, x+6
> x-4, x-2, x, x-6
> x+10, x+8, x+6, x
> x+2, x+4, x+6, x
> x-10, x-8, x-6, x
> x-2, x-4, x-6, x
>
> Solving all the possible combinations, there were three different
> as:
>
> 78, 76, 74, 68
> 70, 72, 74, 80
> 73, 75, 77, 71
>
> All three are correct answers, may be the options had just the
second one as
> option. So they marked only this as correct. But your answer can
never be
> correct.
>
>
>
>
> On 7/16/06, Mitrabhanu Pati <mitrabhanu_p@...> wrote:
> >
> > Hi there,
> > Pl. solve the following puzzle.
> >
> > Q : My friend has four uncles of different height. Their average
height is
> > 74 inches & diference in height amongst the first three uncle is
two inches.
> > The difference between the third & the fourth uncle is 6 inches.
Find out
> > the height of each uncle.
> >
> > PS : I am getting the answer as 63,65,67 & 61. But the answer is
70,72,74
> > & 80. Can anybody solve this for me ????
> >
> > Mit.
> >
>
• I came across a few good problems and would like to share it. but I couldn’t get the solutions to them. Kindly help me out. Q1 A survey was conducted on the
Message 9 of 13 , Aug 25, 2006
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I came across a few good problems and would like to share it. but I couldnt get the solutions to them. Kindly help me out.

Q1 A survey was conducted on the eating habits of a group of 1000 people. Results show that 92 % of the people surveyed eat south Indian food, 91 % eat North Indian food, 82 % eat American food, 78 % eat Chinese food, 79 % eat Italian food and 80 % eat Continental food. What must be the minimum number of people who eat all the 6 types of food, if 7 people do not eat any of the six types of food?

(1)  0                (2) 13               (3) 27               (4) 55

Q 2 There are 2n integers [0,0,1,1,2,2,3,3..(n-1),(n-1)]. From these 2n integers, n integers are chosen such that their average is an integer. Find the minimum average of those chosen n integers, given that n=23.

(1) 4                 (2) 5                 (3) 6                 (4) 7

Q 3 How many integral pairs (x,y) exist such that   x² + 10y² - 4xy + 2x + 8y  18 = 0 ?

(1) two             (2) three           (3) four             (4) six

Q 4 The polynomial equation x4 + ax2 + bx  15 = 0 has 4 real integral solutions. Which among the following may be a possible value of b?

(1)  -15                        (2)  18              (3)  -32            (4) None of these

P(a-b,b)      if  a>= b
Q 5      P(a,b) =
a            if  a < b

it is given that  P(a,7) = 4; P(a,11) = 6 and P(a,13) = 3.
Find P(a,17), if a is a positive integer between 2000 and 3000.

(1) 6                 (2)  8                (3)  11              (4)  12

GAURAV AGARWAL
ELECTRONICS ENGINEERING
FINAL YEAR
INDIAN SCHOOL OF MINES

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• Hi Gaurav, I could solve first two ques, trying 3 &4 and could not understand ques 5. answer: 1) they have asked minimum no, so for each tye of food try
Message 10 of 13 , Sep 24, 2006
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Hi Gaurav,

I could solve first two ques, trying 3 &4 and could not understand ques 5.

1) they have asked minimum no, so for each tye of food try getting the no of ppl not eating that type of food.
100-92=8 , 100-91=9  and so on
add them and it comes to 98% and 7 ppl dont eat any type of food, so ans is 2% of 1000 -7=13

2)minimum average of 23 nos is 66/23, so 4 should be the minimum integer from given choices.

Cheers!

Nitin

gaurav agarwal <chota_newton@...> wrote:

I came across a few good problems and would like to share it. but I couldnt get the solutions to them. Kindly help me out.

Q1 A survey was conducted on the eating habits of a group of 1000 people. Results show that 92 % of the people surveyed eat south Indian food, 91 % eat North Indian food, 82 % eat American food, 78 % eat Chinese food, 79 % eat Italian food and 80 % eat Continental food. What must be the minimum number of people who eat all the 6 types of food, if 7 people do not eat any of the six types of food?

(1)  0                (2) 13               (3) 27               (4) 55

Q 2 There are 2n integers [0,0,1,1,2,2, 3,3..(n-1), (n-1)]. From these 2n integers, n integers are chosen such that their average is an integer. Find the minimum average of those chosen n integers, given that n=23.

(1) 4                 (2) 5                 (3) 6                 (4) 7

Q 3 How many integral pairs (x,y) exist such that   x² + 10y² - 4xy + 2x + 8y  18 = 0 ?

(1) two             (2) three           (3) four             (4) six

Q 4 The polynomial equation x4 + ax2 + bx  15 = 0 has 4 real integral solutions. Which among the following may be a possible value of b?

(1)  -15                        (2)  18              (3)  -32            (4) None of these

P(a-b,b)      if  a>= b
Q 5      P(a,b) =
a            if  a < b

it is given that  P(a,7) = 4; P(a,11) = 6 and P(a,13) = 3.
Find P(a,17), if a is a positive integer between 2000 and 3000.

(1) 6                 (2)  8                (3)  11              (4)  12

GAURAV AGARWAL
ELECTRONICS ENGINEERING
FINAL YEAR
INDIAN SCHOOL OF MINES

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• Answer to Q 2. *Ans : (3) 6* *Solution *: Lets pick the first 23 numbers of the series as our selection i.e. [ 0,0,1,1,2,2,.....9,9,10,10,11.] The sum of these
Message 11 of 13 , Sep 25, 2006
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Ans : (3) 6
Solution : Lets pick the first 23 numbers of the series as our selection i.e. [ 0,0,1,1,2,2,.....9,9,10,10,11.] The sum of these 23 numbers is 2*(1+2+3+....+10)+11 i.e. 2*55+11 = 121. The average will be 121/23 = 5.26 . THis is not an integer.
The nearest interger is 6. We need 23*6 i.e.138 in numerator to get 6. This means 17 more to the total of 121. We can replace a number in the above set so that the net impact is 17+ (Say replacing 0 by 17, 1 by 18 etc).

Also this will be smallest because we have selected the smallest possilble numbers.
Hence ans is 6.

On 8/26/06, gaurav agarwal <chota_newton@...> wrote:

I came across a few good problems and would like to share it. but I couldn't get the solutions to them. Kindly help me out.

Q1 A survey was conducted on the eating habits of a group of 1000 people. Results show that 92 % of the people surveyed eat south Indian food, 91 % eat North Indian food, 82 % eat American food, 78 % eat Chinese food, 79 % eat Italian food and 80 % eat Continental food. What must be the minimum number of people who eat all the 6 types of food, if 7 people do not eat any of the six types of food?

(1)  0                (2) 13               (3) 27               (4) 55

Q 2 There are 2n integers [0,0,1,1,2,2,3,3……..(n-1),(n-1)]. From these 2n integers, n integers are chosen such that their average is an integer. Find the minimum average of those chosen n integers, given that n=23.

(1) 4                 (2) 5                 (3) 6                 (4) 7

Q 3 How many integral pairs (x,y) exist such that   x² + 10y² - 4xy + 2x + 8y – 18 = 0 ?

(1) two             (2) three           (3) four             (4) six

Q 4 The polynomial equation x4 + ax2 + bx – 15 = 0 has 4 real integral solutions. Which among the following may be a possible value of b?

(1)  -15                        (2)  18              (3)  -32            (4) None of these

P(a-b,b)      if  a>= b
Q 5      P(a,b) =
a            if  a < b

it is given that  P(a,7) = 4; P(a,11) = 6 and P(a,13) = 3.
Find P(a,17), if 'a' is a positive integer between 2000 and 3000.

(1) 6                 (2)  8                (3)  11              (4)  12

GAURAV AGARWAL
ELECTRONICS ENGINEERING
FINAL YEAR
INDIAN SCHOOL OF MINES

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Kind Regards
Sumit Sarda
+91 98275 29597
• Q1 Ans is (d) and not (b).......all of the given is not a perfect square. q4 i think ans is (d) -- none of these Here u have to consider that x,y have a
Message 12 of 13 , Nov 17 12:25 AM
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Q1> Ans is (d) and not (b).......all of the given is not a perfect
square.

q4> i think ans is (d) -- none of these
Here u have to consider that x,y have a common domain (2,3), and so
if x=y in this domain, then x-y=0, also x-y can be nagative.....so
lower limit of x-y cannot be said so easily.......and neighter the
ratio.
Abhishek

--- In ascent4cat@yahoogroups.com, aarti jain <aartirjain@...> wrote:
>
> hey pallavi,
> ssup' ...lisn, al dese probs r quite simple...u jus have to use
sum basic rules.
> solutions:
>
> 1) ans is (b)
> a perfect square can neva end in 2,3,7 and 8
>
> 2) i dint get ure Q...as in em not actualy clear bout d Q
>
> 3) u can solve dis sum by takin few eg.
> square of a no. grater den 1000
> say for eg: 1001
> find the square of 1001 wid the formula (1000+1)^2
> ie 1000000+2000+1= 1002001
> test for divisibility for 3 is: sum of the digits of the no.
shud b divisible by 3
> ( for eg: 453 : sum of digits is 12. therefore, the no. is
divisible by 3
> and to find the remainder, divide the sum by 3
> for eg: 454 : sum of digits is 13, the no. is not divisible by 3
n d remaider is 1...( divide 13 by 3)
> here, is dis sum : sum of digits os 1002001 is 4 , so the
remainder is 1
> next, square of 1002 is 1004004 and dis no. is divisible by 3
> square of 1003 is 1006009, it is not divisible by 3 and
remainder is 1.... so on n so forth..
> so the ans is option (a) 1 always
>
> 4) u get the upper limit for x+y wen d value for x and y is
maximum which is 4 and 3 resp in dis case and the lower limit for x-
y is wen d value for x and y is d lowest, which is 2 and 1 resp in
dis case.
> therefore, x+y/x-y = 4+3/2-1
> =7/1
> =7
> which is ans option (b) 7
>
> 5)
> pallavi aggarwal <pal_agg2003@...> wrote:
>
> which of the following is not a perfect square?
>
> a) 1,00,856 b) 3,25,137 c) 9,45,729
d) all of these
>
>
>
> some birds settled on the branches of a tree. Ffirst, they sat
one to a branch and there was one bird too many. Next they sat two
to a branch and there was one branch too many. How many branches
were there?
>
> a) 3 b) 4 c) 5 d) 6
>
>
> the square of a number greater than 1000 that is not divisible
by 3, wen divided by 3, leaves a remainder of
>
> a) 1 always b) 2 always c) either 1 or
2 d)cant be said
>
>
>
> if 2<x<4 and 1<y<3, then find the ratio of the upper limit for
x+y and the lower limit of x-y
>
> a) 6 b) 7 c) 8 d) none of these
>
>
>
>
>
>
> ---------------------------------
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