- hi mansi this is kuldeep here,here is the solution for ur problem:there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?sol:train which starts from A towards B covered 50 kms in 2 hrs as it started 2 hr earlier then the other train.so to meet both of these train ,these trains have to cover 550 kms with a speed of 60 kms/hr (25+35)so time taken is 550/60 hr.so in 550/60 hr train which started from B coveres (550*35)/60=320.833333 kmsso this train at this moment is 600 - 320.833333 = 279.16667 kmshere is the answer
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**From:**ascent4cat@yahoogroups.com [mailto:ascent4cat@yahoogroups.com]**On Behalf Of**mansi suri**Sent:**Wednesday, September 14, 2005 12:41 PM**To:**ascent4cat@yahoogroups.com**Subject:**Re: [ascent CAT] TDShi Ankurthis is mansi ihave a problem on speed time and distance so please help me.the ans i know but i am not getting the exact solution .there are 2 stations 600 km apart. a train starts from first station A and moves towards B at the rate of 25km\h. after 2 hours another train from station B at hte rate of 35km\h. how far from A will they cross each other?

the ans for this is 279.166 kmhope to get the ans soonwrote:*Ankur Aggarwal <ankur.pegasus@...>*1) 2km in ¼ km course = 8 rounds race

middle of 6

^{th}round means 5 and a half round and since that round means an overlap . 4 ½ for the second party .11km for a = 9 km for b

2 km for a = 18/11 km for b

difference = 4/11km

2) 250 A = 200 B

550A = 440 B

so he is short by 10 m

3) let faster takes t minutes for one round.

So in each overtake, number of rounds by slower = 30 /( t+1)

Since faster has a lead of 1 round

30 / (t +1) = 30 /t + 1

obvious factors come to be 5,6 minutes to take a round

On 8/16/05,**praveena_panic3**<praveena_panic3@...> wrote:hey people

plz help me out with these probs.

1.In a 2 km race on a circular course of 1/4 th of a km , A overlaps

B in the middle of his 6th round.By what dist will A win at the

same rate of running?(ans 4/11 km)A & B ru

as per the explanation in my book when A runs 5&1/2 rounds B runs

only 4&1/2 rounds.but how do we know that B runs 4&1/2 rounds.plz

explain the entire prob.

2.A & B start frm the same point to run in opp directions around a

circular path 550 yards in length,A giving B a start of 100

yards.They pass each other when A has run 250 yards.who will come

first to the starting point & at what dist will they be apart?(ans -

A,10 yards)

3.Two runners run in the same direction along a circular track 2 km

long.the faster overtakes the slower on e every 30 min.find their

speeds if the faster one completes a round one min sooner than the

other.(ans 24 km/hr & 20km/hr)

plz plz plz explin in detail.

thanks folks.

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- hi ankursrry but i am not convinced with the approach you have taken to solve the race problem bcoz the place where you have written11 km for A = 9 Km for Bhere it is rounds and not the distance either take 8 rounds instead of 2 km or go on with km that is 11 rounds=2.75 km and 9 rounds=2.25 kmsHence the solution you have put up here for mansi is not correct I supppse .For any problem in my explanation ,revert back to me.

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