- View SourceHi

I came across a few quant probs. n wud like to noe the solutions to some.

Q. A person goes between 4 and 5 and comes back between 5 and 6 and

realises that the clock hands (hour hand and minute hand) interchange

their respective positions. How much time did he remain out of his

respective house?

Q. 20 women can finish a job in 20 days. After each day, one woman

is replaced by a man or a boy alternatively starting with a man.Man is

twice efficient and boy is half efficient as a woman. On which day

does the job get completed?

Q.group of new students who total age is 221 years joins a class,

becoz if which the strength of the class goes up by 50% but the avg

age of the class comes down by 1 year. whats the new avg of the class?

if it is known to be a natural number after the new group of students

have joined, given that the original strength of the class was a digit

number greater than 30.

Please tell me the solutions to these probs.Expecting to hear from u soon. - View Sourcewell your solution is wrong....Consider the acute angle between the minutes hand and the hours hand when he goes out and comes back. Since the hands have exchanged, the angle will remain constant.... Let the angle be x.For the minutes hand:Angle moved by the hand when the person is outside his house is 360-x.Minutes hand moves 6 degrees every minute.Time for which the man stays outside = (360-x)/6Applying similar analogyFor the hours hand:Angle moved when the person is outside the house = xHours hand moves 1/2 degree in a minute.Time for which the man stays outside = 2x minutesNow since we could calculate the time taken in both the cases, they should be equal.i.e. 2x = (360-x)/6 => x = 360/13We could find out the angle between the minutes hand and hours hand.The man stays out for 2x minutes i.e. 720/13 = 55 5/13 minutes.This is the exact answer.Hope you understood the solution.Prakash
wrote:*dear_rita2001 <dear_rita2001@...>*`--- In ascent4cat@yahoogroups.com, Vaibhav Gupta <vaibhavgupta007@g...>`

wrote:

> Hi

> I came across a few quant probs. n wud like to noe the solutions to

some.

>

> Q. A person goes between 4 and 5 and comes back between 5 and 6 and

> realises that the clock hands (hour hand and minute hand) interchange

> their respective positions. How much time did he remain out of his

> respective house?

>

Solution

The man remains out for 55 mins.

Since he goes out between 4 & 5 the hour hand should be on 4 ,&

also as he returns between 5 & 6 the hour hand is on 5. As the hour &

minute hand have exchanged, he has left at 4.25 and returned at 5.20.

So,he remained out for 55 mins.

Is this the answer . Plz inform me if it is correct or not.__________________________________________________

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