- [.2, .2, .1, .1, .1, .1 .1, .1]Notice that these sum to 1.0 (since they are mmutually exclusive and exhaustive possibilities). Because we know they sum to 1.0, if we know the first 7, we must know the last one. The first 7 sum to .9, so the last one must be .1. Therefore, if we want to save space, we can drop the last one:[.2, .2, .1, .1, .1, .1 .1]There are 7 values, and we can derive the fact that the missing 8th value must be .1.-Peter
On Sun, May 18, 2008 at 2:53 AM, meskabnada <meskabnada@...> wrote:

Hi,

In the book p.482 it is mentioned that the full joint distribution

table has seven independent members (2*2*2 - 1 because the number must

sum to 1). I didn't understand why it is 7. the provided explanation is

not clear for me.

Thanks for you cooperation

zayan

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