Formula for lookup table size on page 45
- To try and understand this equation I assumed the following:
number of possible percepts P = 3
lifetime of the agent (number of percepts it will receive) = 3
I the get an answer for the summation of 39. However, if I manually
determine the number of possible ways in which the percepts can be
received I get 15 for the size of the lookup table. Can somebody tell
me what I am not undestanding correctly?
- I'm not sure if you're being consistent in your
definition of P, the possible precepts, since I can't
figure out how you arrived at 15. (I agree with 39).
To make life easy, assume you have a single sensor
which can return one of three values - A, B, or C.
The possible precept combinations can therefore be
I think you'll find (as the formula implies) there are
3 possible combinations after the first input is
received (t=1), there are 3^3 = 9 additonal
combinations when the second input is received (t=2),
and 3^3^3 additional combinations once the 3rd input
is received (t=3). Add them all together, and you can
see the agent would need a total of 39 table entries
to know what action to take based on it's precept
--- kindlencotech <fredkindl@...> wrote:
> To try and understand this equation I assumed the__________________________________________________
> number of possible percepts P = 3
> lifetime of the agent (number of percepts it will
> receive) = 3
> I the get an answer for the summation of 39.
> However, if I manually
> determine the number of possible ways in which the
> percepts can be
> received I get 15 for the size of the lookup table.
> Can somebody tell
> me what I am not undestanding correctly?
> Fred Kindl
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