Re: question 13.9
- Both follow the normal proof methods ....
Note that P(X,Y|e) = P(X,Y,e)/P(e)
and P(X|Y,e) = P(X,Y,e)/P(Y,e)
and P(Y|e) = P(Y,e)/P(e)
The first part is immediate from this.
The second part is almost trivial after this ...
P(X,Y|e) = P(X|Y,e) P(Y|e)
P(X,Y|e) = P(Y|X,e) P(X|e)
Can u finish it off from here?
--- In email@example.com, "brandon_pitt_47"
>solutions out there? it's
> Hope someone can help me with this one. completely stuck. any
> on page 490 about proving the conditionalized version of the generalproduct rule.
> P(X,Y|e) = P(X|Y,e) P(Y|e)
> part b: prove the conditionalized version of Bayes' Rule in
> P(Y|X,e) = P(X|Y,e) P(Y|e)
> ANY HELP WOULD BE GREAT.
- yes, i can. thanks again for your help.
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