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question 13.9

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  • brandon_pitt_47
    Hope someone can help me with this one. completely stuck. any solutions out there? it s on page 490 about proving the conditionalized version of the general
    Message 1 of 3 , Nov 2, 2004
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      Hope someone can help me with this one. completely stuck. any solutions out there? it's
      on page 490 about proving the conditionalized version of the general product rule.

      P(X,Y|e) = P(X|Y,e) P(Y|e)

      part b: prove the conditionalized version of Bayes' Rule in Equation (13.10)

      P(Y|X,e) = P(X|Y,e) P(Y|e)
      ------------
      P(X)

      ANY HELP WOULD BE GREAT.

      thanks,
      brandon
    • j1mmy_n3u7120n
      Both follow the normal proof methods .... Note that P(X,Y|e) = P(X,Y,e)/P(e) and P(X|Y,e) = P(X,Y,e)/P(Y,e) and P(Y|e) = P(Y,e)/P(e) The first part is
      Message 2 of 3 , Nov 13, 2004
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        Both follow the normal proof methods ....

        Note that P(X,Y|e) = P(X,Y,e)/P(e)
        and P(X|Y,e) = P(X,Y,e)/P(Y,e)
        and P(Y|e) = P(Y,e)/P(e)

        The first part is immediate from this.

        The second part is almost trivial after this ...
        Note that,
        P(X,Y|e) = P(X|Y,e) P(Y|e)
        also,
        P(X,Y|e) = P(Y|X,e) P(X|e)

        Can u finish it off from here?
        -- AI

        --- In aima-talk@yahoogroups.com, "brandon_pitt_47"
        <brandon_pitt_47@y...> wrote:
        >
        >
        > Hope someone can help me with this one. completely stuck. any
        solutions out there? it's
        > on page 490 about proving the conditionalized version of the general
        product rule.
        >
        > P(X,Y|e) = P(X|Y,e) P(Y|e)
        >
        > part b: prove the conditionalized version of Bayes' Rule in
        Equation (13.10)
        >
        > P(Y|X,e) = P(X|Y,e) P(Y|e)
        > ------------
        > P(X)
        >
        > ANY HELP WOULD BE GREAT.
        >
        > thanks,
        > brandon
      • Brandon Iskey
        yes, i can. thanks again for your help. brandon __________________________________ Do you Yahoo!? Check out the new Yahoo! Front Page. www.yahoo.com
        Message 3 of 3 , Nov 14, 2004
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          yes, i can. thanks again for your help.

          brandon



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