- Feb 21, 2006Hello,

just for those of you that don't know why:

P(X|e1,e2) = a P(X|e1) P(e2|X,e1)

which is used in different explanations in chapter 15, I have expanded the steps

in the Wikipedia article about the Bayes' theorem:

http://en.wikipedia.org/wiki/Bayes%27_theorem#Extensions_of_Bayes.27_theorem

--

Ivan F. Villanueva B.

artificialidea.com

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