## Re: [TeslaTurbine] Re: Relationship formulas

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• Great post John. Thanks for the diagram. This diagram represents the Tesla turbine, vavular conduit and mechanical oscillator (not the electro-mechanical
Message 1 of 3 , Oct 2, 2000
Great post John. Thanks for the diagram. This diagram represents the
Tesla turbine, vavular conduit and mechanical oscillator (not the
electro-mechanical oscillator)
The patent I have seen suggests useing the mechanical osciallator in
conjunction with the vavular conduit. This basically means attaching a
piston to one end of the mechanical oscillator. In this case the piston
has a vavular conduit from one end to the other. On the compression
stroke air has difficulty passing backward through the vavular conduit.
On the intake stroke air is easily drawn in through the top of the
piston and compressed. Several such pistons can be used in series,on the
same shaft, so that air proceeds through each piston, becoming more
compressed with each stroke.Several such pistons can result in
liquification of air. The stroke of a mechanical oscillator depends on
length and can be from severl hundred to several thousand per minute.
The electro mechanical oscillator can move coils in the hundreds of
pounds at the same speed as light weight coils. As a generator its
efficiency is very high. It can produce a type of direct current and
cause rapid rotation in a Faraday disk.
As to the relationship formula below, there is one I developed which
depends on the area of rotational contact. C= pi D A= pi R squared.
The rotational contact area is equal to the surface area of the disk
multiplied by the rpm. Rpm is determined by the speed of the steam,
under load, this will be half the speed of the incoming steam, without
load it will approach the speed of the incoming steam. These figures are
variable based on the number of disks and air resistance. If a condenser
is used, a hard vacuum will be created at the outlet of the turbine,
reduceing resistance. If heat of vaporization is reclaimed from the
steam, only a fraction of the energy will be necessary to boil the water
into steam.
Tesla suggested useing twice as many rotors in a vacuum turbine as
with the drive turbine to remove air from the containment. Since the
rotors in a vacuum turbine can be made thinner, it would be about the
same weight. The amount of work the vacuum turbine does is only a
fraction of the work the drive turbine does, because it removes trace
amounts of air, compared to the drive turbine which is moved by 27 cubic
foot of steam per pound of water. So work done greatly exceeds work
consumed. The volume of the steam is 27 cubic foot at stp. At 27 HG the
volume of steam may equal 64 cubic foot.
Paul

pixelmedia@... wrote:
>
> I do not know if this will help but see
> Tesla's patent # US01329559 it may be of some help.
> John
>
> Ps Will up load to "files"
>
> --- In TeslaTurbine@egroups.com, "Jim Dooley" <LSUman@m...> wrote:
> > Does anyone have any formulas that deal with predicting the
> performance of a Tesla bladeless device. I am looking for
> mathematical tools to aid in designing several bladeless pumps and
> blowers as well as turbines. I have not come across anything yet
> that will allow me to calculate runner dimensions and output speed
> and torque based on input working fluid parameters. Also, I would
> like any information on stage compounding in the pump configuration.
> Thanks in advance to anyone on the list that can help.
> >
> > Jim Dooley
>
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