Re: True pano resolution (cont.)
- --- In PanoToolsNG@yahoogroups.com, Fabio Bustamante <contato@...> wrote:
> Now I wondered if this relation between the equirectangular resolution
> and the "true" resolution would be the same between the
> equirectangular's area and the surface of the sphere.
> If so...
> In a 6000x3000 pano we could assume this sphere has an equator
> circunference of 6000 pixels.
> If pi x diameter = 6000 then the diameter of this sphere would be of
> about 1910 pixels and the radius 955 pixels.
> Now, the surface's area equation is A = 4 x pi x R^2. So this sphere
> a surface of around 11460844 pixels, or roughly 11.4mp.Yes, but as Erik mentioned in this thread already, it depends on the
> Could it be that simple?
viewing projection used by the user.
One way to simplify the computation above is to use Lambert Equal Area
projection: the number of pixels per surface is always constant
regardless of the pitch. So you only have to multiply its horizontal
and vertical dimensions to get a feeling of its "true resolution".