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Re: Calibration of Lambert Projection Conformal Conic (info Ozi requires)

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  • draulstone
    It works perfectly. Many thanks, JG. Dave Raulstone
    Message 1 of 3 , Jan 1, 2009
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      It works perfectly.
      Many thanks, JG.
      Dave Raulstone

      --- In OziUsers-L@yahoogroups.com, "rwcx183" <lgalvin@...> wrote:
      > --- In OziUsers-L@yahoogroups.com, "draulstone" <draulstone@> wrote:
      > >
      > > I'm new so please excuse my ignorance.
      > >
      > > I have a scanned raster map which has the following notes about its
      > > Projection:
      > > "Lambert Conformal Conic Projection Standard Parallels 9deg 20'and
      > > 14deg 40', Convergence Factor 0.20799".
      > > How do I derive from the above what Ozi calls for, ie latitude 1 &
      > > latitude 2 (are these perhaps the 2 Standard Parallels provided on the
      > > map?); Central Median (is this perhaps the central latitude on the
      > > paper map?) ; Origin Latitiude (can this be derived from the above?)?
      > >
      > > Thank you very much.
      > > Best regards,
      > > Dave Raulstone
      > Dave,
      > Latitude 1 and latitude 2 are indeed the same as standard parallels.
      > It does not matter which one you use for which, though as a matter of
      > consistency, you should enter the standard parallel closest to the
      > equator, as latitude 1. Central meridian is actually the central
      > longitude of the projection and technically, may or may not be down the
      > center of the map image. In fact, unless there is a printed lambert
      > grid on the map image that you intend to use, it does not matter what
      > value you enter for central meridian. Here again for consistency,
      > enter a value that corresponds to the longitude down the middle of the
      > map image, if you do not know the actual value. The value used for
      > origin latitude does not matter either, unless you're going to use
      > lambert grid coordinates. So, just enter 0 for latitude origin.
      > J.G.
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