## FW: 3 count run-around

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• Yeh, so the 9th pass is the same as the first. This correlates with my experience in the run-around side, as does your B B B A A A A B list at the bottom,
Message 1 of 2 , May 11 8:01 AM
Yeh, so the 9th pass is the same as the first. This correlates with my
experience in the run-around side, as does your "B B B A A A A B" list at
the bottom, which shows the first passer doing exclusively self throws for
what feels like a long time after an initial burst. Yew Is A Genius.

Learning this with a pair of clubs in the passing slots which differ from
the other clubs (which always are self throws) seems necessary to work out
the cycle. This also means that you and Madison got about 1.5 times around
the cycle at the end of last night, when I counted a total of 12 three-count
passes as I was posting.

So the passing pattern is time-symetrical, right? An ongoing cycle would be
"B B B [A A A A] [B B B B} [A A A A] . . ."? Hmm. Some patterns in this
group are not time-symetrical in this fashion -- think, for example, of a
4-count with one side being two people half-juggling. There, if I am acting
the left hand, I never pass a club to anyone but my near-side partner. I
wonder if any time-asymetrical run-around patterns exist. I kind of think
not, but I'm not sure I could prove it.

Man, I wonder if anyone else in the world has done this stuff. We better
hustle up another person and try two facing 3-count run-arounds.

-- CHS

> -----Original Message-----
> From: Carl Raffa [SMTP:craffa@...]
> Sent: Friday, May 11, 2001 10:18 AM
> Subject: 3 count run-around
>
> The 3 count run-around pattern repeats after 8 passes. The easiest way
> to analyze it is by looking at the throws. The throws in the basic
> run-around look like this:
>
>
> B throws right to B's left
> A throws left to A's right
> A throws right to B's left
> B throws left to B's right
>
> B is now in front and A is in back:
>
> A throws right to A's left
> B throws left to B's right
> B throws right to A's left
> A throws left to A's right
>
> So, the basic run-around repeats after 8 throws.
>
> We can use the least common multiple to determine how a composite
> pattern repeats. With a 4 count, the solution is simple. The least
> common multiple of 4 and 8 is 8, so the whole pattern repeats every 8
> throws. We have to look at the run-around pattern to see who gets to
> pass. If you look at the 1st and 5th throws, you will see that B gets
> the first pass and A gets the second pass.
>
> Now, the 3 count is a bit more complex. The least common multiple of 3
> and 8 is 24! So, the whole pattern repeats every 24 throws. Again, the
> look at the run-around pattern to see who gets to pass. The pass
> sequence is B, B, B, A, A, A, A, B.
>
> Carl
• ... You can also start the pattern anywhere in the sequence. Our usual fast start has been with B behind, slightly to the right, with a club in the right
Message 2 of 2 , May 11 9:07 AM
Charles Shapiro wrote:
> So the passing pattern is time-symetrical, right? An ongoing cycle would be
> "B B B [A A A A] [B B B B} [A A A A] . . ."?

You can also start the pattern anywhere in the sequence. Our usual fast
start has been with B behind, slightly to the right, with a club in the
right hand. The first throw is B's right hand throw, which is a pass,
but leads to the BBBAAAAB pattern. Last night, we were able to slow
start directly into AAAABBBB by having B's first throw be a self throw,
and having A's first throw be a left hand pass. To fast start directly
into AAAABBBB we could start with B behind, slightly to the left, with a
club in the left hand, and have A throw the club in his left hand as the
first pass. In either case, though this requires A to start with a left
hand pass. I can't see a way to fast start into the AAAABBBB pattern
without a left hand pass. Unless we reverse the direction of the
run-around, of course.

As for a non-symmetrical pattern, an 8 count, or any multiple of an 8
count, would result in only one person getting to pass. But who wants
to wait around for an 8 count? A 7 count repeats every 56 throws with
pass pattern BABBABAA. A 6 count repeats every 24 throws with pass
pattern BBAA. A 5 count repeats every 40 throws with pass pattern
BBAAAABB. A 4 count repeats every 8 throws with pass pattern BA. A 3
count repeats every 24 throws with pass pattern BBBAAAAB. A 2 count
repeats every 8 throws with pass pattern BAAB. A 1 count repeats every
8 throws with pass pattern BAABABBA. That would be fun to try.

The end result is that anything other than a multiple of an 8 count will
always have an equal number of throws for each person. To get an
unequal number of passes, you'd have to have a mixed count. For
example, a 3 count followed by a 2 count followed by a 3 count would
only let B throw (assuming our standard start). You may be able to
accomplish the same thing by reversing the direction of the run-around,
but I haven't worked it out yet.

Carl

Hmm. Some patterns in this
> group are not time-symetrical in this fashion -- think, for example, of a
> 4-count with one side being two people half-juggling. There, if I am acting
> the left hand, I never pass a club to anyone but my near-side partner. I
> wonder if any time-asymetrical run-around patterns exist. I kind of think
> not, but I'm not sure I could prove it.
>
> Man, I wonder if anyone else in the world has done this stuff. We better
> hustle up another person and try two facing 3-count run-arounds.
>
> -- CHS
>
> > -----Original Message-----
> > From: Carl Raffa [SMTP:craffa@...]
> > Sent: Friday, May 11, 2001 10:18 AM
> > To: Charles Shapiro; mad@...
> > Subject: 3 count run-around
> >
> > The 3 count run-around pattern repeats after 8 passes. The easiest way
> > to analyze it is by looking at the throws. The throws in the basic
> > run-around look like this:
> >
> >
> > B throws right to B's left
> > A throws left to A's right
> > A throws right to B's left
> > B throws left to B's right
> >
> > B is now in front and A is in back:
> >
> > A throws right to A's left
> > B throws left to B's right
> > B throws right to A's left
> > A throws left to A's right
> >
> > So, the basic run-around repeats after 8 throws.
> >
> > We can use the least common multiple to determine how a composite
> > pattern repeats. With a 4 count, the solution is simple. The least
> > common multiple of 4 and 8 is 8, so the whole pattern repeats every 8
> > throws. We have to look at the run-around pattern to see who gets to
> > pass. If you look at the 1st and 5th throws, you will see that B gets
> > the first pass and A gets the second pass.
> >
> > Now, the 3 count is a bit more complex. The least common multiple of 3
> > and 8 is 24! So, the whole pattern repeats every 24 throws. Again, the
> > look at the run-around pattern to see who gets to pass. The pass
> > sequence is B, B, B, A, A, A, A, B.
> >
> > Carl
>
> ----------
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