- Topics
*Topics* - TrendingSkip to main content
*Trending*

# Topics List

### Perspective Triangles

(3)

[Stalislav Takhayev]: Any triangle of ABC, I-incenter. The outer Soddy circle is constructed.Points of contact of three mutually tangent of a circles with
Antreas Hatzipolakis

Sep 17

### Bicentric points

(4)

[APH] Let ABC be a triangle. The perpendicular to AB at A intersects BC at A1 The perpendicular to BC at B intersects CA at B1 The perpendicular to CA at C
Antreas Hatzipolakis

Sep 12

### I, Reflected Euler lines

(7)

[APH]: Let ABC be a triangle, P a point and A'B'C' the pedal triangle of P. Denote: La, Lb, Lc = the Euler lines of PBC, PCA, PAB, resp. L1, L2, L3 = the
Antreas Hatzipolakis

Sep 12

Fetching Sponsored Content...

### Orthogonal circle

(3)

[APH]: Let ABC be a triangle and A'B'C', A"B"C" the pedal triangles of O,H, resp. The orthogonal circle ( = radical circle) of the circles (A', A'A"), (B',
Antreas Hatzipolakis

Sep 12

### N, Reflected Euler lines

(5)

[APH]: Let ABC be a triangle, P a point and A'B'C' the pedal triangle of P. Denote: La, Lb, Lc = the Euler lines of AB'C', BC'A', CA'B', resp. L1, L2, L3 = the
Antreas Hatzipolakis

Sep 9

### A problem related to Artzt parabolas

(3)

[APH]: A Greek mathematician (F. D. Constantinides) published a paper on Artzt parabolas, where writes the following conjecture: If from a given triangle ABC
Antreas Hatzipolakis

Sep 3

## Trending Topics

See All- Perspective Triangles 3 Posts
- Bicentric points 4 Posts
- I, Reflected Euler lines 7 Posts
- Orthogonal circle 3 Posts
- N, Reflected Euler lines 5 Posts

View First Topic
Go to
View Last Topic