# Topics List

### Orthologic triangles -- Locus

(5)

[APH]: Let ABC be a triangle and P a point. Denote: Pa = (Reflection of BC in PB) /\ (Reflection of BC in PC) Pb = (Reflection of CA in PC) /\ (Reflection of
Antreas Hatzipolakis

Mar 7

### I - Concurrent NPCs

(6)

On Wed, Mar 4, 2015 at 7:11 PM, Antreas Hatzipolakis wrote: Let ABC be a triangle. ... ************************ On Wed, Mar 4, 2015 at 8:51 PM, Moses, Peter J.
Antreas Hatzipolakis

Mar 6

### Reflections - Loci

(3)

1. La, Lb, Lc are concurrent? (the entire plane, with point of concurrence the isogonal conjugate of P) Confirmed 2. ABC, A'B'C' are perspective? (the entire
Antreas Hatzipolakis

Feb 26

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### Re: Point on the IH line

(4)

[APH]: The perpendiculars to HIa, HIb, HIc from A,B,C, resp. bound triangle A"B"C". Which point is the circumenter of A"B"C" ? Is it lying on the IH line? ...
Antreas Hatzipolakis

Feb 24

### Collinear Points

(10)

... *********************************************** [César Lozada] It is X(1141). [Peter Moses] Hi Antreas, X(1141). Best regards Peter. [APH]: [APH]: Let ABC
Antreas Hatzipolakis

Feb 19

### Interesting circle

(4)

... Extraversions: Following are "theoretic" ie written without drawings. Hope they are true..... :-) We have two incircles in the configuration, so there
Antreas Hatzipolakis

Feb 11

### Cyclology of hexagon

(6)

From: Angel Montesdeoca [Attachment(s) <#14b5bc8ac33fefb1_TopText> from Angel Montesdeoca included below] Let's rewrite the Anopolis #2404 and Anopolis #2406
Antreas Hatzipolakis

Feb 5

### A property of X(597) and a locus

(6)

Dear Seiichi, The Eulerline through the centroids of quadrangles made from 4 centroids, 4 circumcenters, and 4 orthocenters of its component triangles is the
Antreas Hatzipolakis

Jan 29

### Reflections - NPCs - Cyclologic triangles

(4)

... Discussion here: https://www.facebook.com/photo.php?fbid=773944689348296&set=a.237986886277415.57448.100001983178784&type=1&theater APH
Antreas Hatzipolakis

Jan 28

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