Where is the incenter ?
- Dear John,
The squared distance between the incenter I and the center of the
orthocentroidal circle (midpoint of GH) is, in terms of a, b, c:
the cyclic sum
Sigma [4a^6 - 6a^5(b+c) - 4a^4(b^2+c^2) + 12b^3c^3 + 21a^4bc
- 15a^3bc(b+c) + 39a^2b^2c^2]
divided by 36SS, S being twice the area.
I shall try to understand the rest of your message.