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RE: [EMHL] The orthic limit.

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  • Michael Lambrou
    ... of ... intersect at ... centre of ... You are absolutely right. Thanks and sorry to everybody. Michael.
    Message 1 of 9 , Jun 5, 2002
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      >
      > > The "mid-point" triangles are also inscribed in the above sequence
      of
      > > Euler circles. It is obvious that these mid-point triangles
      intersect at
      > > the
      > > entre of gravity G of the original triangle (which is also the
      centre of
      > > gravity of each triangle in the sequence).
      > > Hence the intresection point of the orthic triangles is G, which
      > > settles question 2).
      >
      > But this I don't think is true. In fact for a narrow isosceles
      > triangle,
      > the orthic triangle is all near the base, while the centroid isn't, so
      > indeed your argument is wrong.
      >

      You are absolutely right. Thanks and sorry to everybody.

      Michael.
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