RE: [EMHL] The orthic limit.
> > The "mid-point" triangles are also inscribed in the above sequence
> > Euler circles. It is obvious that these mid-point trianglesintersect at
> > thecentre of
> > entre of gravity G of the original triangle (which is also the
> > gravity of each triangle in the sequence).You are absolutely right. Thanks and sorry to everybody.
> > Hence the intresection point of the orthic triangles is G, which
> > settles question 2).
> But this I don't think is true. In fact for a narrow isosceles
> the orthic triangle is all near the base, while the centroid isn't, so
> indeed your argument is wrong.