Re: [EMHL] Greetings and a problem
- Stanley Rabinowitz wrote:
>Let A1A2A3 be a triangle.The circle (C1) touches A1A2 at Ca, and A3A1 at Ba
>Inside the triangle are the 3 Malfatti circles
>with centers C1, C2, C3. (C1 closest to A1, etc.)
>Let A2C3 meet A3C2 at B1.
>Let A3C1 meet A1C3 at B2.
>Let A1C2 meet A2C1 at B3.
>Then (conjecture) A1B1, A2B2, A3B3
>are concurrent at a point P.
The circle (C2) touches A2A3 at Ab, and A1A2 at Cb
The circle (C3) touches A3A1 at Bc, and A2A3 at Ac
A' = A2Bc /\ A3Cb. Similarly B', C'.
A" = A2Ba /\ A3Ca. Similarly B", C".
Are the triangles A'B'C', A"B"C" in perspective with ABC?