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Re: Six NPC Centers

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  • Antreas
    [APH] ... The radical axes of ((Nab),(Nac)), ((Nbc),(Nba)),((Nca),(Ncb)) are concurrent. Which is the point of concurrence? APH
    Message 1 of 4 , Apr 1, 2013
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      [APH]
      > Let ABC be a triangle and A'B'C' the cevian triangle of P.
      >
      > Denote:
      >
      > Nab = The NPC center of AA'B'
      >
      > Nac = The NPC center of AA'C'
      >
      > Nbc = The NPC center of BB'C'
      >
      > Nba = The NPC center of BB'A'
      >
      > Nca = The NPC center of CC'A'
      >
      > Ncb = The NPC center of CC'B'
      >
      > 2. P = H (A'B'C' = orthic triangle)

      The radical axes of ((Nab),(Nac)), ((Nbc),(Nba)),((Nca),(Ncb))
      are concurrent.

      Which is the point of concurrence?

      APH
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