## Re: A question from Louis Rogliano

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• For any P={u:v:w} the tangential triangle of the circumcevian triangle of P is perspective with ABC. The perspector is the isogonal conjugate of the point
Message 1 of 2 , Mar 10, 2013
For any P={u:v:w} the tangential triangle of the circumcevian triangle of P is perspective with ABC. The perspector is the isogonal conjugate of the point Q=(c^2 u v+b^2 u w-a^2 v w:c^2 u v-b^2 u w+a^2 v w:-c^2 u v+b^2 u w+a^2 v w). In the particular case of P=G, the perspector is Q=X25.

Best regards,

Francisco Javier.

--- In Hyacinthos@yahoogroups.com, Jean-Louis Ayme <jeanlouisayme@...> wrote:
>
> Dear Haycinthists,
> I receive to day a question from L. Rogliano:
> 1. ABC a triangle
> 2. G the median point of ABC
> 3. A'B'C' the G-circumcevian of ABC
> 4. A"B"C" the tangential triangle of A'B'C'
> ï¿½
> I know that A"A, BB", CC" are concurrent at X the Steinbart point of ABC.
> ï¿½
> Question : L. Rogliano want to know if X is in ETC.
> Waiting for a response,
> Sincerely
> Jean-Louis
>
> [Non-text portions of this message have been removed]
>
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