- Let ABC be a triangle and A'B'C' the cevian triangle of I.
B'a, C'a = the reflections of B',C' in AA', resp.
A'a = (perpendicular to BB' from B'a) /\ (perpendicular to CC' from
C'b, A'b = the reflections of C',A' in BB', resp.
B'b = (perpendicular to CC' from C'b) /\ (perpendicular to AA' from
A'c, B'c = the reflections of A',B' in CC', resp.
C'c = (perpendicular to AA' from A'c) /\ (perpendicular to BB' from
Are the circumcircles of A'aB'aC'a, B'bC'bA'b, C'cA'cB'c
Let Ia,Ib,Ic be the incenters of A'aB'aC'a, B'bC'bA'b, C'cA'cB'c,
Are the triangles ABC, IaIbIc perspective?
- The circumcircles of AaAbAc, BaBbBc, CaCbCc are concurrent on the NPC circle of A'B'C'.AaAbAc, BaBbBc, CaCbCc = the pedal triangles of A", B", C", wrt triangle A'B'C' resp.Let ABC be a triangle, P a point and A'B'C' the pedal triangle of P.Denote:L = the Euler line of A'B'C'A", B", C" = orthogonal projections of A, B, C, on L, resp.The point of concurrence is the reflection point of L wrt the medial triangle of A'B'C'.Problem:Let ABC be a triangle and L a line.For which points P's the L is the Euler line of the pedal triangle of P ?APH