## Re: [EMHL] changes in point of view

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• Dear Chris May be you can look at this theorem in the other way. A projective map f of the plane and a point O are given. Then the locus of the point M such
Message 1 of 3 , Dec 11, 2012
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Dear Chris
May be you can look at this theorem in the other way.
A projective map f of the plane and a point O are given.
Then the locus of the point M such that O, M, f(M) are on a same line is
the conic thru O, f^{-1}(O) and the three fixed points of f.
Merry Xmas and Happy New Year
Francois

On Sun, Dec 9, 2012 at 8:48 AM, Chris Van Tienhoven <van10hoven@...>wrote:

> **
>
>
> Dear friends,
>
> Here is my december contribution.
>
> One of the major theorems in Projective Geometry (see the book of P.S.
> Modenow and A.S. Parkmohenko [1, page 24]) states:
> Given any four points A, B, C, D of a projective plane Pi, no three of
> which are collinear, and four points A', B', C', D' of a projective plane
> Pi', no three of which are collinear, there exists one and only one
> projective mapping T of Pi onto Pi' that takes A, B, C, D into A', B', C',
> D', respectively.
> I wondered what happens to the points in the triangle field of A,B,C
> performing this transformation.
> In short: the field is stretched. All points change position except A,B,C.
> Then I wondered how this could be constructed. I found 3 ways of
> construction.
> The simplest (with the use of conics):
> 1. Let ABC be a random Triangle.
> 2. Let D1 and D2 and P1 be random points unequal to each other and unequal
> A, B or C.
> 3. We are looking for the point P2 being the ABCD1-ABCD2-Transformation of
> P1.
> 4. Construct the Conic Co1 through A,B,C,D1,D2.
> 5. Let S1 be the 2nd intersection point of Co1 and the line D1.P1.
> 6. Construct the Conic Co2 through A,B,C,P1,S1.
> 7. Now P2 = the 2nd intersection point of Co2 and the line D2.S1.
> Note: the 2nd intersection point of a conic and a line can be constructed
> by straightedge only.
>
> Then some other remarkable items:
> 1. The locus of a ABCD1->ABCD2 Projective Transformation of the
> circumcircle is a circumscribed conic.
> 2. Note that all transformation vectors are directed to/from the same
> point S on the circumcircle, which is the 4th intersection of the
> circumcircle and the mapped conic.
> 3. Note that the 4th intersection point of the circumcircle and the
> circumscribed conic ABC.D1.D2 is collinear with D2 and S.
> Using this property S can be constructed when only D1 and D2 are known.
> 4. The same properties occur when the circle is interchanged for a
> circumscribed conic.
>
> Finally:
> Let X1 be some random point.
> Let X2 be the Projective ABCD1->ABCD2-Transformation of X1.
> Let Co be the Conic through ABC and X1 and X2.
> Theorem:
> Now all transformation-vectors of the same Projective
> ABCD1->ABCD2-Transformation of points on this conic will point to X2.
>
> So the X1-X2-circumscribed conic is the locus of all points that are
> D1-D2-mapped with transformation direction to X2.
> Further:
> a. The Transformation vector at X2 is tangent at the conic.
> b. Let S1 = D1.X1 ^ D2.X2. This point is on the conic Co.
> c. The Transformation vector in S1 has the direction of D2.X2.
>
> It all might seem a bit theoretical, but when you make pictures, it comes
> to live.
> I can send Cabri-pictures for those interested.
>
> Algebraic implications
> I calculated what happens to a random point P(x0 : y0 : z0), when another
> random point D1 (x1 : y1 : z1) in the projective plane defined by points A,
> B, C, D1 is changed into D2 (x2 : y2 : z2). The algebraic outcome is
> amazingly simple: (x0.x2/x1 : y0.y2/y1 : z0.z2/z1).
>
> Note that a projective transformation actually is a projected picture as
> seen under perspective. Sometimes even projected twice.
> The ABCD1->ABCD2 Projection Transformation can be described as two
> consecutive changes of point of view (one finite and one infinite).
> Probably several items already are known under some name. I am interested
>
> Best regards,
>
> Chris van Tienhoven
>
> [1] P.S. Modenow and A.S. Parkmohenko, Geometric Transformations, Volume
> 2: Projective Transformations, p.24 Two fundamental Theorems on Projective
> Transformations.
>
>
>

[Non-text portions of this message have been removed]
• Thanks Francois, I also received interesting personal mails from Francisco and from Eckart Schmidt. According to Eckart Schmidt there is a striking accordance
Message 2 of 3 , Dec 21, 2012
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Thanks Francois,

I also received interesting personal mails from Francisco and from Eckart Schmidt.
According to Eckart Schmidt there is a striking accordance between a projective D1-D2-Transformation and an Isoconjugate (see [1]).
When:
Q2 = (P1,P2)  Isoconjugate of Q1.
then:
Q2 = (Q1,P2)  ProjectiveTransformation of P1, or
P2 = (P1,Q2)  ProjectiveTransformation of Q1.
This shows:
1. Indeed the Isoconjugate is a Projective Transformation.
2. There is a cross-wise use of parameters for Isoconjugates and P1P2-Projective Transformations.

Best regards,

Chris van Tienhoven

[1] Jean-Pierre Ehrmann and Bernard Gibert, Special Isocubics in the Triangle Plane, available at:
http://bernard.gibert.pagesperso-orange.fr/files/isocubics.html

--- In Hyacinthos@yahoogroups.com, Francois Rideau <francois.rideau@...> wrote:
>
> Dear Chris
> May be you can look at this theorem in the other way.
> A projective map f of the plane and a point O are given.
> Then the locus of the point M such that O, M, f(M) are on a same line is
> the conic thru O, f^{-1}(O) and the three fixed points of f.
> Merry Xmas and Happy New Year
> Francois
>
> On Sun, Dec 9, 2012 at 8:48 AM, Chris Van Tienhoven <van10hoven@...>wrote:
>
> > **
> >
> >
> > Dear friends,
> >
> > Here is my december contribution.
> >
> > One of the major theorems in Projective Geometry (see the book of P.S.
> > Modenow and A.S. Parkmohenko [1, page 24]) states:
> > Given any four points A, B, C, D of a projective plane Pi, no three of
> > which are collinear, and four points A', B', C', D' of a projective plane
> > Pi', no three of which are collinear, there exists one and only one
> > projective mapping T of Pi onto Pi' that takes A, B, C, D into A', B', C',
> > D', respectively.
> > I wondered what happens to the points in the triangle field of A,B,C
> > performing this transformation.
> > In short: the field is stretched. All points change position except A,B,C.
> > Then I wondered how this could be constructed. I found 3 ways of
> > construction.
> > The simplest (with the use of conics):
> > 1. Let ABC be a random Triangle.
> > 2. Let D1 and D2 and P1 be random points unequal to each other and unequal
> > A, B or C.
> > 3. We are looking for the point P2 being the ABCD1-ABCD2-Transformation of
> > P1.
> > 4. Construct the Conic Co1 through A,B,C,D1,D2.
> > 5. Let S1 be the 2nd intersection point of Co1 and the line D1.P1.
> > 6. Construct the Conic Co2 through A,B,C,P1,S1.
> > 7. Now P2 = the 2nd intersection point of Co2 and the line D2.S1.
> > Note: the 2nd intersection point of a conic and a line can be constructed
> > by straightedge only.
> >
> > Then some other remarkable items:
> > 1. The locus of a ABCD1->ABCD2 Projective Transformation of the
> > circumcircle is a circumscribed conic.
> > 2. Note that all transformation vectors are directed to/from the same
> > point S on the circumcircle, which is the 4th intersection of the
> > circumcircle and the mapped conic.
> > 3. Note that the 4th intersection point of the circumcircle and the
> > circumscribed conic ABC.D1.D2 is collinear with D2 and S.
> > Using this property S can be constructed when only D1 and D2 are known.
> > 4. The same properties occur when the circle is interchanged for a
> > circumscribed conic.
> >
> > Finally:
> > Let X1 be some random point.
> > Let X2 be the Projective ABCD1->ABCD2-Transformation of X1.
> > Let Co be the Conic through ABC and X1 and X2.
> > Theorem:
> > Now all transformation-vectors of the same Projective
> > ABCD1->ABCD2-Transformation of points on this conic will point to X2.
> >
> > So the X1-X2-circumscribed conic is the locus of all points that are
> > D1-D2-mapped with transformation direction to X2.
> > Further:
> > a. The Transformation vector at X2 is tangent at the conic.
> > b. Let S1 = D1.X1 ^ D2.X2. This point is on the conic Co.
> > c. The Transformation vector in S1 has the direction of D2.X2.
> >
> > It all might seem a bit theoretical, but when you make pictures, it comes
> > to live.
> > I can send Cabri-pictures for those interested.
> >
> > Algebraic implications
> > I calculated what happens to a random point P(x0 : y0 : z0), when another
> > random point D1 (x1 : y1 : z1) in the projective plane defined by points A,
> > B, C, D1 is changed into D2 (x2 : y2 : z2). The algebraic outcome is
> > amazingly simple: (x0.x2/x1 : y0.y2/y1 : z0.z2/z1).
> >
> > Note that a projective transformation actually is a projected picture as
> > seen under perspective. Sometimes even projected twice.
> > The ABCD1->ABCD2 Projection Transformation can be described as two
> > consecutive changes of point of view (one finite and one infinite).
> > Probably several items already are known under some name. I am interested
> >
> > Best regards,
> >
> > Chris van Tienhoven
> >
> > [1] P.S. Modenow and A.S. Parkmohenko, Geometric Transformations, Volume
> > 2: Projective Transformations, p.24 Two fundamental Theorems on Projective
> > Transformations.
> >
> >
> >
>
>
> [Non-text portions of this message have been removed]
>
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