## Another way to find the complement of a point w/r a triangle.

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• The complement of P w/r a triangle ABC is the point P’ such as vector GP’ = vector GP / 2, where G is the triangle centroid. Another way to find P’: 1)
Message 1 of 2 , Jan 30, 2012
The complement of P w/r a triangle ABC is the point P such as vector GP =
vector GP / 2, where G is the triangle centroid.

Another way to find P:

1) Let ABC be the cevian triangle of P

2) Let A the symmetrical point of P w/r to the midpoint of BC and
build B and C analogously.

3) AA, BB and CC meet in P.

Regards.

[Non-text portions of this message have been removed]
• Typo: Vector (GP’) = vector (PG) /2 Sorry. _____ De: Hyacinthos@yahoogroups.com [mailto:Hyacinthos@yahoogroups.com] En nombre de César Lozada Enviado el:
Message 2 of 2 , Jan 30, 2012
Typo:

Vector (GP) = vector (PG) /2

Sorry.

_____

De: Hyacinthos@yahoogroups.com [mailto:Hyacinthos@yahoogroups.com] En nombre
Enviado el: Martes, 31 de Enero de 2012 02:19 a.m.
Para: Hyacinthos@yahoogroups.com
Asunto: [EMHL] Another way to find the complement of a point w/r a triangle.

The complement of P w/r a triangle ABC is the point P such as vector GP =
vector GP / 2, where G is the triangle centroid.

Another way to find P:

1) Let ABC be the cevian triangle of P

2) Let A the symmetrical point of P w/r to the midpoint of BC and
build B and C analogously.

3) AA, BB and CC meet in P.

Regards.

[Non-text portions of this message have been removed]

[Non-text portions of this message have been removed]
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