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Another way to find the complement of a point w/r a triangle.

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  • César Lozada
    The complement of P w/r a triangle ABC is the point P’ such as vector GP’ = vector GP / 2, where G is the triangle centroid. Another way to find P’: 1)
    Message 1 of 2 , Jan 30, 2012
      The complement of P w/r a triangle ABC is the point P’ such as vector GP’ =
      vector GP / 2, where G is the triangle centroid.



      Another way to find P’:

      1) Let A’B’C’ be the cevian triangle of P

      2) Let A” the symmetrical point of P w/r to the midpoint of B’C’ and
      build B” and C” analogously.

      3) AA”, BB” and CC” meet in P’.



      Regards.



      [Non-text portions of this message have been removed]
    • César Lozada
      Typo: Vector (GP’) = vector (PG) /2 Sorry. _____ De: Hyacinthos@yahoogroups.com [mailto:Hyacinthos@yahoogroups.com] En nombre de César Lozada Enviado el:
      Message 2 of 2 , Jan 30, 2012
        Typo:



        Vector (GP’) = vector (PG) /2



        Sorry.



        _____

        De: Hyacinthos@yahoogroups.com [mailto:Hyacinthos@yahoogroups.com] En nombre
        de César Lozada
        Enviado el: Martes, 31 de Enero de 2012 02:19 a.m.
        Para: Hyacinthos@yahoogroups.com
        Asunto: [EMHL] Another way to find the complement of a point w/r a triangle.





        The complement of P w/r a triangle ABC is the point P’ such as vector GP’ =
        vector GP / 2, where G is the triangle centroid.

        Another way to find P’:

        1) Let A’B’C’ be the cevian triangle of P

        2) Let A” the symmetrical point of P w/r to the midpoint of B’C’ and
        build B” and C” analogously.

        3) AA”, BB” and CC” meet in P’.

        Regards.

        [Non-text portions of this message have been removed]





        [Non-text portions of this message have been removed]
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