Typo:

Vector (GP) = vector (PG) /2

Sorry.

_____

De:

Hyacinthos@yahoogroups.com [mailto:

Hyacinthos@yahoogroups.com] En nombre

de César Lozada

Enviado el: Martes, 31 de Enero de 2012 02:19 a.m.

Para:

Hyacinthos@yahoogroups.com
Asunto: [EMHL] Another way to find the complement of a point w/r a triangle.

The complement of P w/r a triangle ABC is the point P such as vector GP =

vector GP / 2, where G is the triangle centroid.

Another way to find P:

1) Let ABC be the cevian triangle of P

2) Let A the symmetrical point of P w/r to the midpoint of BC and

build B and C analogously.

3) AA, BB and CC meet in P.

Regards.

[Non-text portions of this message have been removed]

[Non-text portions of this message have been removed]