Dear Hyacinthists,

6 points on a circle leads to 60 hexagones and 60 Pascal's lines.

These 60 Pascal's lines intersect in 20 Steiner's points.

What is the geometric rule when we sta

Dear Hyacinthists,

6 points on a circle leads to 60 cyclic hexagons and 60 Pascal's lines.

These 60 Pascal's lines intersect in 20 Steiner's points which are triple...

Now, what is the geometric rule in order to obtain the Steiner's points?

For example we start withe the cyclic hexagon ABCDEF. How do we obtain geometrically the two other hexagons? I don't wish to use the term of permutation...

Any geometric ideas?

Sincerely

Jean-Louis

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