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Reference of Golden Number construction

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  • Francisco Javier
    The following construction of the golden number is very well-known and very easy to prove: Given the segment AB, (1) Erect BC perpendicular to AB. (2) Find the
    Message 1 of 3 , Mar 7, 2011
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      The following construction of the golden number is very well-known and very easy to prove:

      Given the segment AB,
      (1) Erect BC perpendicular to AB.
      (2) Find the midpoint D of AB.
      (3) Describe an arc with radius DC and D as center, intersecting the ray AB at E.
      Then AE/AB = golden number.

      Does this construction date back to the greeks? Some reference?
    • Etienne Rousee
      ... You forget to precise AB=BC. -- Etienne
      Message 2 of 3 , Mar 8, 2011
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        Le 08/03/2011 08:38, Francisco Javier a écrit :
        > The following construction of the golden number is very well-known and
        > very easy to prove:
        >
        > Given the segment AB,
        > (1) Erect BC perpendicular to AB.
        > (2) Find the midpoint D of AB.
        > (3) Describe an arc with radius DC and D as center, intersecting the ray
        > AB at E.
        > Then AE/AB = golden number.

        You forget to precise AB=BC.

        --

        Etienne
      • Francisco Javier
        Of course, you are right.
        Message 3 of 3 , Mar 8, 2011
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          Of course, you are right.

          --- In Hyacinthos@yahoogroups.com, Etienne Rousee <etienne@...> wrote:
          >
          > Le 08/03/2011 08:38, Francisco Javier a �crit :
          > > The following construction of the golden number is very well-known and
          > > very easy to prove:
          > >
          > > Given the segment AB,
          > > (1) Erect BC perpendicular to AB.
          > > (2) Find the midpoint D of AB.
          > > (3) Describe an arc with radius DC and D as center, intersecting the ray
          > > AB at E.
          > > Then AE/AB = golden number.
          >
          > You forget to precise AB=BC.
          >
          > --
          >
          > Etienne
          >
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