Re: [EMHL] Lemoine circles and point
- Dear Francois,
> I send you 3 Cabri-drawings on the Lemoine configuration seen in anI think you'll have to place your drawings in the "Files" section of
> hyperbolic framework.
the Hyacinthos group because attachments and graphics are not allowed
in group messages
see > [Non-text portions of this message have been removed]
Greetings from Bruges
- Dear friends
I notice the following fact certainly well known for a long time and very
easy to prove:
Call P any point in the plane of triangle ABC and L the trilinear polar of P
Call Gamma the inscribed conic in ABC of which P is the perspector or
Brianchon point, i.e : P is the perspector of ABC and the contact triangle.
Let M be any point on Gamma and call T the tangent in M at Gamma.
Then the trilinear pole O of T is on L.
From this fact can we find :
1°a simple projective construction of the tangent T of M at Gamma.
2°If O is any point on L, a simple projective construction of the contact
point M of the trilinear polar T of O wrt ABC with Gamma.
Thanks for your swift replies
[Non-text portions of this message have been removed]