- Jun 30, 2014[Randy Hutson]:[APH]:AntreasWhich point is the center of the circle?I think the points Ja,Jb,Jc and I are concyclic.is lying on the circumcircle of IAB.of IAB bound a triangle whose the incenter or an excenter Jcthe circumcircle of ICA and the reflections of Lc in the sidelinesSimilarly, the reflections of Lb in the sidelines of ICA boundcircumcircle of IBC.whose the incenter or an excenter, call it Ja, is lying on theThe reflections of La in the sidelines of IBC bound a triangleLet La, Lb, Lc be the Brocard axes of IBC,ICA,IAB resp.That is:(they are concurrent as well) and take the points by the generalized reflection theorem?How about if we replace the Euler lines with Brocard axes (OK-lines)A natural question is this:The points Ea,Eb,Ec are lying on the circle with diameter OI.Similarly Eb, Ec.lying on the circumcircle of IBC)(ie the point of concurrence of La in the sidelines of IBC,Ea = the reflection of point of La wrt triangle IBCDenote:Sometime ago I posted this:Let ABC be a triangle and La, Lb, Lc the Euler lines of IBC,ICA,IAB, resp.

a triangle, whose the incenter or an excenter Jb is lying on

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Dear Antreas,

The circle as center X(4295) [corrected: X(4297)], segment X(1)X(20) as diameter, and also passes through X(3109).

Best regards,

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