22168Construction of the isog. conjugate of a point by perp. bisectors
- Apr 21, 2014APHSynthetic proof?The perpendicular bisectors of A2A3, B3B1, C1C2Similarly B3,B1 and C1,C2A2, A3 = the reflections of Ab, Ac in AC, AB, resp.Ab, Ac = the reflections of A' in BB', CC', resp.Let ABC be a triangle, P a point and A'B'C' the cevian triangle of P.Denote:
concur at the isogonal conjugate of P.
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