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22074A locus

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  • Antreas Hatzipolakis
    Mar 27, 2014
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      Let ABC be a triangle, P a point and A'B'C' the antipedal
      triangle of P.

      Which is the locus of P such that the O of ABC is lying
      on the Euler line of A'B'C'?

      PS:  We can ask also for other than O points, but why especially for O?
      Because K is on the locus, since  for P = K we have that 
      O(of ABC) = G(of A'B'C'). How to prove it synthetically?

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