- Mar 27, 2014APHBecause K is on the locus, since for P = K we have thatPS: We can ask also for other than O points, but why especially for O?on the Euler line of A'B'C'?Which is the locus of P such that the O of ABC is lyingLet ABC be a triangle, P a point and A'B'C' the antipedaltriangle of P.

O(of ABC) = G(of A'B'C'). How to prove it synthetically?

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