21306[EMHL] Re: another conjugation
- Nov 20, 2012Dear Bernard,
After looking at it more closely, it looks like F(P) is the X(48)-isoconjugate of P, or equivalently, the trilinear product of X(92) and the isogonal conjugate of P.
--- In Hyacinthos@yahoogroups.com, Bernard Gibert <bg42@...> wrote:
> Dear Randy,
> > Question: Is there a construction of this mapping that does not involve the polar circle, which is only defined for obtuse triangles?
> your F(P) is the H-isoconjugate of P i.e. the image of P under the isoconjugation that swaps G and H.
> best regards
> [Non-text portions of this message have been removed]
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