Loading ...
Sorry, an error occurred while loading the content.

21257Re: A conic centered at Euler line

Expand Messages
  • Francisco Javier
    Oct 26, 2012
    • 0 Attachment
      Sorry for the character codes,

      See

      http://garciacapitan.blogspot.com.es/2012/10/a-conic-centered-at-euler-line.html

      for a more readable version

      --- In Hyacinthos@yahoogroups.com, "Francisco Javier" <garciacapitan@...> wrote:
      >
      > I found the following:
      >
      > Theorem. Given a triangle ABC, call Γ the locus of points P such that polar of P with respect to the circumcircle is tangent to the nine point circle. Then we have:
      > 1) Γ is a conic whose center is X26, the circumcenter of the tangential triangle.
      > 2) Γ is an ellipse, parabola o hyperbola if and only if the triangle is acute, triangle or obtuse.
      > 3) The diameter on the transverse axis of the conic is also a diameter of the circumcircle of tangential triangle. Therefore, the transverse axis of the conic is the Euler line of the triangle.
      > 4) If α, β are the lengths of the transverse and conjugate axes of the conic respectively, we have the relation
      >
      > (αβ)^2=1−OH^2/R^2
      >
      > 5) The foci of the conic are O and O′, where O′ is the reflection of O on the center X26.
      >
    • Show all 4 messages in this topic