19878Re: [EMHL] A generalization...
- Mar 1, 2011
> Let ABC be a triangle P = (x:y:z) a point, A'B'C'It's a cubic, 0=cyclic sum of
> the cevian triangle of a point Q = (u:v:w).
> Which is the locus of P such that the circles
> (APA'),(BPB'),(CPC') are coaxial?
>It's a quartic, 0=cyclic sum of a^4 SA (bbzz-ccyy)yz
> Specialcase: P,Q are isogonal conjugate points.
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