15394Re:Cevian Trace Equal Area Points
- Aug 1, 2007Dear Tuan,
> I have found this point and this construction byYes the same method I also used.
> combine following small well known elementary locus
> problem into triangle:
> Two segments XY, X'Y' are on given two lines. To
> find the locus of Z such that Area(ZXY) =
> If areas are not signed then the locus is two
> lines passing intersection of two given lines.
If A is the intersection of XY, X'Y' and
M, M' are the mid points of XY', X'Y
then the locus such that the signed areas
are equal is the line parallel to MM' that
passes through A.
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