15355Re: [EMHL] line/conic intersection
- Jul 2 10:15 AMConstruct (with R&C) the intersection of a line <r>
with a conic (parabola) given by its focus <F> and
I will reply directly from the archives.
I have never received the message below.
To help me (you) in the future: look for msgs
15338-342, 15344, 15352.
I am still experiecing problems sending/receiving msgs.
Sorry for double postings.
The center of C is one of the intersections sought.
Otherwise perform a homothecy of C of pole P.
Please, gimme exactly your construction with your homothecy!
I will suppose the "ideal" position of the data.
Let P=d/\r. With P_0 on r as center draw a circle C
tangent to d. Let P_1 be the contact point.
Draw s=(P,F) and let F_1 and F_2 be the intersections
between <s> and <C>. Draw t=(P_0,F_1) and u=(P_0,F_2).
Draw from <F> t'||t and u'||u. The intersections O=r/\t'
and O'=r/\u' are the intersections of <r> and the parabola.
Your solution seems nice but I still have to
--- In Hyacinthos@yahoogroups.com, "Francois Rideau" <francois.rideau@...>
I think we have a big problem when <d> and <r> are
I don't think so. In this case one has P=d/\r and with P
as pole one makes a homothecy. Draw a circle C with center
in r and tangent do d. If C goes through F fine.
>That's just the problem of this construction: to find circles tangent to
>the directrix <d> and through the focus <F> of which the centers are on
>line <r>. These centers are the sought points of intersection. These
>circles are also on point <F'> symmetric of <F> wrt line <r>. So these
>circles are in a pencil and their intersections with <d> are in involution,
>(Desargues theorem). For example, if <Gamma> is a circle in this pencil
>cutting <d> in <P> and <Q>, then JP.JQ = JF.JF' = power of J wrt <Gamma>,
>(product of oriented segments), where J = FF' /\ <d>. In case of a touching
>circle in T, we have JT² = JF.JF'. The circle of center J and radius JT is
>orthogonal to all circles of the pencil. So draw any circle of the pencil
>and draw segments tangents to this circle through J and so on...
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